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Direction (Q. Nos. 27-30) This section contains 4 questions. when worked out will result in an integer from 0 to 9 (both inclusive)
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For hydrocarbon with molecular formula C5H8, how many acyclic isomers without consecutive pi-bonds are possible?
Correct answer is '3'. Can you explain this answer?
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Direction (Q. Nos. 27-30) This section contains 4questions. when worke...
C5H8 has the following three isomers :
CH3CH2CH2C≡CH
CH3CH2CH2C≡CH
CH3CH2C≡CCH3
(CH3)2CH−C≡CH
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Direction (Q. Nos. 27-30) This section contains 4questions. when worke...
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Direction (Q. Nos. 27-30) This section contains 4questions. when worke...
Acyclic Isomers of C5H8 without Consecutive Pi-bonds
To determine the number of acyclic isomers of C5H8 without consecutive pi-bonds, we need to consider the different ways in which the carbon atoms can be arranged in a chain.
Isomer 1:
- The first isomer will have a straight chain of 5 carbon atoms with a double bond at one end and a methyl group at another carbon atom.
- This arrangement satisfies the given molecular formula C5H8 without having consecutive pi-bonds.
Isomer 2:
- The second isomer will have a branched chain with a double bond between two carbon atoms and a methyl group attached to the third carbon atom.
- This arrangement also satisfies the given molecular formula and the condition of no consecutive pi-bonds.
Isomer 3:
- The third isomer will have a cyclic structure with 5 carbon atoms forming a ring and a double bond within the ring.
- This cyclic structure fulfills the molecular formula requirement and the condition of no consecutive pi-bonds.
Therefore, there are 3 possible acyclic isomers of C5H8 without consecutive pi-bonds.
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Direction (Q. Nos. 27-30) This section contains 4questions. when worked out will result in an integer from 0 to 9 (both inclusive)Q.For hydrocarbon with molecular formula C5H8, how many acyclic isomers without consecutive pi-bonds are possible?Correct answer is '3'. Can you explain this answer?
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Direction (Q. Nos. 27-30) This section contains 4questions. when worked out will result in an integer from 0 to 9 (both inclusive)Q.For hydrocarbon with molecular formula C5H8, how many acyclic isomers without consecutive pi-bonds are possible?Correct answer is '3'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Direction (Q. Nos. 27-30) This section contains 4questions. when worked out will result in an integer from 0 to 9 (both inclusive)Q.For hydrocarbon with molecular formula C5H8, how many acyclic isomers without consecutive pi-bonds are possible?Correct answer is '3'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Direction (Q. Nos. 27-30) This section contains 4questions. when worked out will result in an integer from 0 to 9 (both inclusive)Q.For hydrocarbon with molecular formula C5H8, how many acyclic isomers without consecutive pi-bonds are possible?Correct answer is '3'. Can you explain this answer?.
Direction (Q. Nos. 27-30) This section contains 4questions. when worked out will result in an integer from 0 to 9 (both inclusive)Q.For hydrocarbon with molecular formula C5H8, how many acyclic isomers without consecutive pi-bonds are possible?Correct answer is '3'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Direction (Q. Nos. 27-30) This section contains 4questions. when worked out will result in an integer from 0 to 9 (both inclusive)Q.For hydrocarbon with molecular formula C5H8, how many acyclic isomers without consecutive pi-bonds are possible?Correct answer is '3'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Direction (Q. Nos. 27-30) This section contains 4questions. when worked out will result in an integer from 0 to 9 (both inclusive)Q.For hydrocarbon with molecular formula C5H8, how many acyclic isomers without consecutive pi-bonds are possible?Correct answer is '3'. Can you explain this answer?.
Solutions for Direction (Q. Nos. 27-30) This section contains 4questions. when worked out will result in an integer from 0 to 9 (both inclusive)Q.For hydrocarbon with molecular formula C5H8, how many acyclic isomers without consecutive pi-bonds are possible?Correct answer is '3'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
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