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An electron placed in a uniform electric Field, experience an electric force equal to its weight mg.Find the intensity of the field?
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An electron placed in a uniform electric Field, experience an electric...
Intensity of the Electric Field
The intensity of the electric field can be calculated using the formula:
E = F/q
Where:
- E is the electric field intensity
- F is the electric force experienced by the electron
- q is the charge of the electron
Given Information
The electric force experienced by the electron is equal to its weight which is given by:
F = mg
Where:
- m is the mass of the electron
- g is the acceleration due to gravity
Equating the Forces
Since the electric force is equal to the weight of the electron, we can set the two equations equal to each other:
mg = qE
This equation allows us to solve for the electric field intensity E:
E = mg/q
Substitute Known Values
We know the mass of an electron is approximately 9.11 x 10^-31 kg and the charge of an electron is approximately 1.6 x 10^-19 C. The acceleration due to gravity is approximately 9.81 m/s^2.
Substitute these values into the equation:
E = (9.11 x 10^-31 kg * 9.81 m/s^2) / (1.6 x 10^-19 C)
E = 5.60 x 10^11 N/C
Therefore, the intensity of the electric field is 5.60 x 10^11 N/C.
The intensity of the electric field can be calculated using the formula:
E = F/q
Where:
- E is the electric field intensity
- F is the electric force experienced by the electron
- q is the charge of the electron
Given Information
The electric force experienced by the electron is equal to its weight which is given by:
F = mg
Where:
- m is the mass of the electron
- g is the acceleration due to gravity
Equating the Forces
Since the electric force is equal to the weight of the electron, we can set the two equations equal to each other:
mg = qE
This equation allows us to solve for the electric field intensity E:
E = mg/q
Substitute Known Values
We know the mass of an electron is approximately 9.11 x 10^-31 kg and the charge of an electron is approximately 1.6 x 10^-19 C. The acceleration due to gravity is approximately 9.81 m/s^2.
Substitute these values into the equation:
E = (9.11 x 10^-31 kg * 9.81 m/s^2) / (1.6 x 10^-19 C)
E = 5.60 x 10^11 N/C
Therefore, the intensity of the electric field is 5.60 x 10^11 N/C.
Community Answer
An electron placed in a uniform electric Field, experience an electric...
Mg=qE so E=mg/q
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An electron placed in a uniform electric Field, experience an electric force equal to its weight mg.Find the intensity of the field?
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An electron placed in a uniform electric Field, experience an electric force equal to its weight mg.Find the intensity of the field? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about An electron placed in a uniform electric Field, experience an electric force equal to its weight mg.Find the intensity of the field? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An electron placed in a uniform electric Field, experience an electric force equal to its weight mg.Find the intensity of the field?.
An electron placed in a uniform electric Field, experience an electric force equal to its weight mg.Find the intensity of the field? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about An electron placed in a uniform electric Field, experience an electric force equal to its weight mg.Find the intensity of the field? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An electron placed in a uniform electric Field, experience an electric force equal to its weight mg.Find the intensity of the field?.
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