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5 coins are tossed. If two of them show heads , then the probability that all 5 coins show head is
  • a)
    1/32
  • b)
    1/10
  • c)
    1/26
  • d)
    1/13
  • e)
    1/15
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
5 coins are tossed. If two of them show heads , then the probability t...
Let p = prob (head) = 0.5
1 - p  = prob (tail) = 0.5

The probability of obtain at least 2 heads is equivalent to 1 -  {P (0 heads) + P ( 1 head) }

P ( 0 heads) = (0.5)^5 = 1/32
P ( 1 head)  = 5 x (0.5)^4 x 0.5 = 5/32

So, the answer is:

1 - (1/32 + 5/32) = 26/32  = 13/16  =
= 0.8125
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5 coins are tossed. If two of them show heads , then the probability that all 5 coins show head isa)1/32b)1/10c)1/26d)1/13e)1/15Correct answer is option 'C'. Can you explain this answer?
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