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At certain temperature, 50% of HI is dissociated into H2 and I2, the equilibrium constant is
  • a)
    1.0
  • b)
    3.0
  • c)
    0.5
  • d)
    0.25
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
At certain temperature, 50% of HI is dissociated into H2 and I2, the e...
Let the entire reaction take place in a vessel of Volume V
Given the equation
2HI= I2 + H2
Here let initial moles of HI=N. Moles vanished=y
So at time=0   N=   0       0
At time =t
N-2y= y      y
Given 50% of HI dissociates. So conc. of HI left=50%
So we can say
N-2y=50%of N
N-2y=N/2
2y=N-N/2
y=N/4
[I2] =N/4V=[H2]
[HI] =N/2V
So  Kc=[I2].[H2]/[HI]^2
Kc=(N^2/16)/(N^2/4)     =(N^2x4)/(N^2x16)     =4/16     =0.25
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At certain temperature, 50% of HI is dissociated into H2 and I2, the equilibrium constant isa)1.0b)3.0c)0.5d)0.25Correct answer is option 'D'. Can you explain this answer?
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At certain temperature, 50% of HI is dissociated into H2 and I2, the equilibrium constant isa)1.0b)3.0c)0.5d)0.25Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about At certain temperature, 50% of HI is dissociated into H2 and I2, the equilibrium constant isa)1.0b)3.0c)0.5d)0.25Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for At certain temperature, 50% of HI is dissociated into H2 and I2, the equilibrium constant isa)1.0b)3.0c)0.5d)0.25Correct answer is option 'D'. Can you explain this answer?.
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