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The general value of θ which satisfies the equations sinθ=-(1/2) and tanθ=(1/√3) is
  • a)
  • b)
    nπ + (π/6)
  • c)
    nπ - (π/6)
  • d)
    2nπ + (7π/6)
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
The general value of θ which satisfies the equations sinθ=...
Hence in third quodrant sin-1/2 and tan1√3 are common so
angle (thitha)=210
in π term thitha=210×π/180=7π/6
thitha=2nπ+alpha
here alpha=7π/6
so thitha=2nπ+7π/6
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The general value of θ which satisfies the equations sinθ=-(1/2) and tanθ=(1/√3) isa)b)nπ + (π/6)c)nπ - (π/6)d)2nπ + (7π/6)Correct answer is option 'D'. Can you explain this answer?
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The general value of θ which satisfies the equations sinθ=-(1/2) and tanθ=(1/√3) isa)b)nπ + (π/6)c)nπ - (π/6)d)2nπ + (7π/6)Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The general value of θ which satisfies the equations sinθ=-(1/2) and tanθ=(1/√3) isa)b)nπ + (π/6)c)nπ - (π/6)d)2nπ + (7π/6)Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The general value of θ which satisfies the equations sinθ=-(1/2) and tanθ=(1/√3) isa)b)nπ + (π/6)c)nπ - (π/6)d)2nπ + (7π/6)Correct answer is option 'D'. Can you explain this answer?.
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