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A circular steel wire 2.00 m long must stretch no more than 0.25 cm when a tensile force of 400 N is applied to each end of the wire. What minimum diameter is required for the wire?
  • a)
    1.4 mm
  • b)
    10 mm
  • c)
    1.5 mm
  • d)
    12.4 mm
Correct answer is option 'A'. Can you explain this answer?
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A circular steel wire 2.00 m long must stretch no more than 0.25 cm wh...
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A circular steel wire 2.00 m long must stretch no more than 0.25 cm wh...
Given:

- Length of circular steel wire, l = 2.00 m
- Maximum stretch allowed, Δl = 0.25 cm = 0.0025 m
- Tensile force applied, F = 400 N

To find: Minimum diameter required for the wire

Formula used:

- Young's modulus of elasticity, Y = (F/A) / (Δl/l)
- Cross-sectional area of wire, A = πd²/4

Calculation:

- Substitute the given values in the formula for Young's modulus:

Y = (400/A) / (0.0025/2.00)

- Substitute the formula for cross-sectional area in the above equation:

Y = (400/πd²/4) / (0.0025/2.00)

- Simplify the above equation:

Y = 32,000,000/d²

- Solve for diameter, d:

d² = 32,000,000/Y

d = √(32,000,000/Y)

- Substitute the value of Young's modulus for steel, Y = 2.0 x 10¹¹ N/m²:

d = √(32,000,000/2.0 x 10¹¹)

d = 0.0014 m = 1.4 mm

Therefore, the minimum diameter required for the wire is 1.4 mm.

Answer: (a) 1.4 mm
Community Answer
A circular steel wire 2.00 m long must stretch no more than 0.25 cm wh...
First we should know Young's Modulus of steel then apply its formula
change in length is 0.25cm
l=2m. T=400 A=πr2. then diameter
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A circular steel wire 2.00 m long must stretch no more than 0.25 cm when a tensile force of 400 N is applied to each end of the wire. What minimum diameter is required for the wire?a)1.4 mmb)10 mmc)1.5 mmd)12.4 mmCorrect answer is option 'A'. Can you explain this answer?
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