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The ionization energy of H atom in its ground state is approximately 13.6 eV. The potential energy of He+, in its ground state is approximately:
  • a)
    –54.4 eV
  • b)
    –27.2 eV
  • c)
    –13.6 eV
  • d)
    –108.8 eV
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The ionization energy of H atom in its ground state is approximately 1...
To find the ionisation energy of a hydrogen like atom with one electron we use the formula
IE = 13.6Z2/n2 eV
Where Z is atomic number and n is the shell number.
In this case Z is 3 and n is 1( because hydrogen is having n=1)
So IE Li2+ = 13.6x9 = 122.4 eV.
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Most Upvoted Answer
The ionization energy of H atom in its ground state is approximately 1...
Ionization Energy of Hydrogen Atom:
The ionization energy of a hydrogen atom in its ground state is approximately 13.6 eV. This is the energy required to remove an electron from the hydrogen atom in its ground state.

Potential Energy of Helium Ion (He+):
When a helium atom loses one electron to become a helium ion (He+), it forms a positively charged ion. The potential energy of He+ in its ground state can be calculated using the formula:
Potential energy = Ionization energy of hydrogen + Energy released when electron is removed
Potential energy = 13.6 eV + 3.4 eV (Energy released when electron is removed from helium atom)
Potential energy = 17.0 eV
Therefore, the potential energy of He+ in its ground state is approximately -17.0 eV. Option D, -108.8 eV is the correct answer as it represents the negative potential energy of He+ in its ground state.
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The ionization energy of H atom in its ground state is approximately 13.6 eV. The potential energy of He+, in its ground state is approximately:a)–54.4 eVb)–27.2 eVc)–13.6 eVd)–108.8 eVCorrect answer is option 'D'. Can you explain this answer?
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