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In H-atom, if ‘x’ the radius of this Bohr-orbit, de Broglie wavelength of an e in 3rd orbit is:
  • a)
  • b)
  • c)
    9x/2
  • d)
    x/2
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
In H-atom, if ‘x’ the radius of this Bohr-orbit, de Brogli...
For a hydrogen atom, radius of nth orbit, rn = n2h2/ 4π2mZe2 Therefore, r1/r3 = 12/32 r3 = 9/r1 = 9/xNow, according to De Broglie; angular momentum of electron in 3rd orbit is:mvr3 = 3h/2π or h/mv = 2πr3/3Andλ = h/mv where, λ is the de Broglie wavelength.Therefore,λ = 2πr3/3 = 2π x 9/3x = 6πx
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In H-atom, if ‘x’ the radius of this Bohr-orbit, de Broglie wavelength of an e– in 3rd orbit is:a)b)c)9x/2d)x/2Correct answer is option 'B'. Can you explain this answer?
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