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Consider a CFG with the following productions. S → AA | B A → 0A | A0 | 1 B → 0B00 | 1 S is the start symbol, A and B are non-terminals and 0 and 1 are the terminals. The language generated by this grammar is
  • a)
    {0n 102n | n ≥ 1}
  • b)
    {0i 10j 10k | i, j, k ≥ 0} ∪ {0n 102n | n ≥ l}
  • c)
    {0i 10j | i, j ≥ 0} ∪ {0n 102n | n ≥ l}
  • d)
    The set of all strings over {0, 1} containing at least two 0's
  • e)
    None of the above
Correct answer is option 'E'. Can you explain this answer?
Verified Answer
Consider a CFG with the following productions. S → AA | B A U...
A− > 0A|A0|1 This production rule individually produces a CFL of the form {0^i 10^j |i, j ≥ 0}
B− > 0B00|1 This production rule individually produces a CFL of the form {0^n10^2n |n ≥ 0}
S− > AA|B This production rule concatenates A’s CFL with itself and unions it with B’s CFL.
Hence, CFL accepted by the given CFG will be {0^n10^2n|n ≥ 0} ∪ {0^i 10^j 10^k |i, j, k ≥ 0}
According to our derivation, as none of the given CFL matches to our derived CFL, correct option
should be (E) None of the above.
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Most Upvoted Answer
Consider a CFG with the following productions. S → AA | B A U...

Explanation:

Given CFG Productions:
- S → AA | B
- A → 0A | A0 | 1
- B → 0B00 | 1

Language Generated:
The language generated by the given CFG is not explicitly defined in the options provided. The CFG generates strings that consist of alternating sequences of 0s and 1s, with some specific patterns.

Analysis of CFG Productions:
1. S → AA | B: This production allows for the generation of strings with two A's or directly a B.
2. A → 0A | A0 | 1: This production allows for the generation of strings starting or ending with 0, or containing a single 1.
3. B → 0B00 | 1: This production generates strings starting with 0, followed by a B, and ending with 00.

Conclusion:
The language generated by the given CFG is a combination of sequences of 0s and 1s with specific patterns defined by the productions. Since none of the options provided match the exact patterns generated by the CFG, the correct answer is None of the above (option E).
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Consider a CFG with the following productions. S → AA | B A → 0A | A0 | 1 B → 0B00 | 1 S is the start symbol, A and B are non-terminals and 0 and 1 are the terminals. The language generated by this grammar isa){0n102n| n ≥ 1}b){0i10j10k| i, j, k ≥ 0} ∪ {0n102n| n ≥ l}c){0i10j| i, j ≥ 0} ∪ {0n102n| n ≥ l}d)The set of all strings over {0, 1} containing at least two 0'se)None of the aboveCorrect answer is option 'E'. Can you explain this answer?
Question Description
Consider a CFG with the following productions. S → AA | B A → 0A | A0 | 1 B → 0B00 | 1 S is the start symbol, A and B are non-terminals and 0 and 1 are the terminals. The language generated by this grammar isa){0n102n| n ≥ 1}b){0i10j10k| i, j, k ≥ 0} ∪ {0n102n| n ≥ l}c){0i10j| i, j ≥ 0} ∪ {0n102n| n ≥ l}d)The set of all strings over {0, 1} containing at least two 0'se)None of the aboveCorrect answer is option 'E'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Consider a CFG with the following productions. S → AA | B A → 0A | A0 | 1 B → 0B00 | 1 S is the start symbol, A and B are non-terminals and 0 and 1 are the terminals. The language generated by this grammar isa){0n102n| n ≥ 1}b){0i10j10k| i, j, k ≥ 0} ∪ {0n102n| n ≥ l}c){0i10j| i, j ≥ 0} ∪ {0n102n| n ≥ l}d)The set of all strings over {0, 1} containing at least two 0'se)None of the aboveCorrect answer is option 'E'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a CFG with the following productions. S → AA | B A → 0A | A0 | 1 B → 0B00 | 1 S is the start symbol, A and B are non-terminals and 0 and 1 are the terminals. The language generated by this grammar isa){0n102n| n ≥ 1}b){0i10j10k| i, j, k ≥ 0} ∪ {0n102n| n ≥ l}c){0i10j| i, j ≥ 0} ∪ {0n102n| n ≥ l}d)The set of all strings over {0, 1} containing at least two 0'se)None of the aboveCorrect answer is option 'E'. Can you explain this answer?.
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