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The reductive ozonolysis of an alkene gave butanone and propanol. Write the structure of alkene and its IUPAC name?
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The reductive ozonolysis of an alkene gave butanone and propanol. Writ...
Structure and IUPAC name of the alkene:

The reductive ozonolysis of an alkene resulted in the formation of butanone and propanol. To determine the structure and IUPAC name of the alkene, we can work backward from the products.

Butanone:
Butanone, also known as methyl ethyl ketone, has the molecular formula C4H8O. It is a ketone with a carbonyl group (C=O) attached to an internal carbon atom. The IUPAC name for butanone is 2-butanone.

Propanol:
Propanol, also known as 1-propanol, has the molecular formula C3H8O. It is an alcohol with a hydroxyl group (-OH) attached to the first carbon atom of the alkyl chain. The IUPAC name for propanol is propan-1-ol.

Deducing the structure:
To deduce the structure of the alkene, we need to consider the products obtained from the reductive ozonolysis.

Butanone:
Butanone is a ketone, indicating that one of the carbons in the alkene must have been part of a double bond. The suffix "-one" indicates that the carbonyl group is attached to an internal carbon atom. Based on this information, we can deduce that the alkene must be a four-carbon chain with a double bond between the second and third carbon atoms.

Propanol:
Propanol is an alcohol, indicating that one of the carbons in the alkene must have been part of a double bond. The suffix "-ol" indicates the presence of a hydroxyl group (-OH) attached to the first carbon atom of the alkyl chain. Based on this information, we can deduce that the alkene must be a three-carbon chain with a double bond between the first and second carbon atoms.

Structure and IUPAC name:
Based on the deductions made above, the structure of the alkene can be determined as follows:

CH3-CH=CH-CH3

The IUPAC name for this alkene is 2-butene. The name indicates that it is a four-carbon chain with a double bond between the second and third carbon atoms. The presence of the double bond is responsible for the reactivity observed during the reductive ozonolysis, leading to the formation of butanone and propanol.
Community Answer
The reductive ozonolysis of an alkene gave butanone and propanol. Writ...
I think its not propanol its propanal
Ans would be 3-Methylhexa-3-ene
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The reductive ozonolysis of an alkene gave butanone and propanol. Write the structure of alkene and its IUPAC name?
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