For a given kinetic energy of the following has the smallest de Broglie wavelength electron, proton, Alpha particles?

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For a given kinetic energy of the following has the smallest de Broglie wavelength electron, proton, Alpha particles?

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For a given kinetic energy of the following has the smallest de Brogli...

Alpha particles have the greatest m, so they have the smallest λ. De broglie wavelength lambda=h/mv, where m is the mass of the particle. More the mass, lesss the wavelength. The alpha particle has the highest mass, so it has the shortest wavelength.Wavelength is shortest for alpha particles because

Lemda =√(h/2mk)

From the above formula we have,

Lamda is inversly proportional to mass

Wavelength is shorter for greater mass

As alpha partical has more mass so it has shorter wavelength

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For a given kinetic energy of the following has the smallest de Brogli...

Alpha particles

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For a given kinetic energy of the following has the smallest de Broglie wavelength electron, proton, Alpha particles?

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