Two bodies of masses m and 4 m are moving with equal kinetic energy. The ratio of velocities with which they are traveling is :a)3:4b)2:1c)4:5d)1:2Correct answer is option 'B'. Can you explain this answer?

Question

Answer

Lets say the velocity of ‘m’ is ‘v’ and velocoty of ‘4m’ is ‘u’
Therefore, mv = 4mu ———————— Given
So, v = 4u
Now we know that kienetic energy = (1/2) mv^2
Thus for the ratio, we need to calculate
(1/2 * m * (4u)^2) / (1/2 * 4m * u^2)
Turns out to be 4/1.
Which means the ratio of keinetic energies of both masses is 4:1
Hope its help uhh...if u like then plzz upvote.

Answer

Ke of 1st body =1/2mv^2..... equation
ke of 2nd body =1./2 4m v^2...... equation 2

ratio of equation 1 and equation 2
.1/2mv^2=1/2*4m *v2
so it will be 1:4 answer...

Answer

Kinetic energy of 1st body=1/2mv^2
=1/2×mv^2....eq(1)

kinetic energy of 2nd body=1/2mv^2
=1/2×4m×v^2......eq(2)

comparing eq (1) and (2)

1st body : 2nd body

1/2mv^2 = 1/2×4mv^2

=>1:4(Ans).

Answer

Given:
- Two bodies with masses m and 4m
- Both bodies have equal kinetic energy

To find:
The ratio of velocities with which they are traveling

Explanation:

1. Kinetic Energy:
The kinetic energy (KE) of an object is given by the formula:
KE = 1/2 * m * v^2

Where:
- KE is the kinetic energy
- m is the mass of the object
- v is the velocity of the object

Since both bodies have equal kinetic energy, we can set up the equation:

1/2 * m * v1^2 = 1/2 * 4m * v2^2

2. Simplifying the equation:
Let's simplify the equation by canceling out common terms:

m * v1^2 = 4m * v2^2

Now, divide both sides of the equation by m:

v1^2 = 4v2^2

3. Taking square roots:
To isolate the velocities, we take the square root of both sides:

√(v1^2) = √(4v2^2)

Simplifying further:

v1 = 2v2

4. Ratio of velocities:
The ratio of the velocities can be written as:

v1 : v2 = 2 : 1

Therefore, the correct answer is option 'B' - 2:1.

Answer

K.e =1/2 mv^2
1/2mv^2 : 1/2(4m)v^2
v^2 : 4 v^2
1:4

Similar Class 9 Doubts

Two objects of masses 1 x 10^-3 kg and 4 x 10^-3 kg have equal momentum. What is the ratio of their kinetic energies?

Two bodies A and B having masses 2 kg and 4kg respectively are separated by 2 m. Where should a body of mass 1 kg be placed so that the gravitational force on this body due to bodies A and B is zero?

Two bodies of mass 1 kg and 100 kg respectively are dropped simultaneously from same height 4.9m in vacuum.Calculate and compare their final velocities just before hitting the ground and the time interval in which they will hit the ground?

Two bodies A and B having masses 20 kg and 40 kg are separated 10 M at what distance from body A should another body C of mass 15 kg we place so that the net gravitation force on C is zero?

Using newton law of gravitation show that if the earth exert equal force on two bodies held near it then their masses are equal?

Top Courses for Class 9View all

Science Class 9

Social Studies (SST) Class 9

Mathematics (Maths) Class 9

English Grammar Advanced

English Class 9

Top Courses for Class 9

Top Courses for Class 9

Suggested Free Tests

Related Content

Class 9 Study Material

Class 9 Subjects

Competitive Examinations for Class 9

NCERT Books

NCERT Solutions

Reference Books for Class 9

Other Popular Exams

Company