Two bodies of masses m and 4 m are moving with equal kinetic energy. The ratio of velocities with which they are traveling is :a)3:4b)2:1c)4:5d)1:2Correct answer is option 'B'. Can you explain this answer?

Question

Answer

Lets say the velocity of ‘m’ is ‘v’ and velocoty of ‘4m’ is ‘u’
Therefore, mv = 4mu ———————— Given
So, v = 4u
Now we know that kienetic energy = (1/2) mv^2
Thus for the ratio, we need to calculate
(1/2 * m * (4u)^2) / (1/2 * 4m * u^2)
Turns out to be 4/1.
Which means the ratio of keinetic energies of both masses is 4:1
Hope its help uhh...if u like then plzz upvote.

Answer

Ke of 1st body =1/2mv^2..... equation
ke of 2nd body =1./2 4m v^2...... equation 2

ratio of equation 1 and equation 2
.1/2mv^2=1/2*4m *v2
so it will be 1:4 answer...

Answer

Kinetic energy of 1st body=1/2mv^2
=1/2×mv^2....eq(1)

kinetic energy of 2nd body=1/2mv^2
=1/2×4m×v^2......eq(2)

comparing eq (1) and (2)

1st body : 2nd body

1/2mv^2 = 1/2×4mv^2

=>1:4(Ans).

Answer

Given:
- Two bodies with masses m and 4m
- Both bodies have equal kinetic energy

To find:
The ratio of velocities with which they are traveling

Explanation:

1. Kinetic Energy:
The kinetic energy (KE) of an object is given by the formula:
KE = 1/2 * m * v^2

Where:
- KE is the kinetic energy
- m is the mass of the object
- v is the velocity of the object

Since both bodies have equal kinetic energy, we can set up the equation:

1/2 * m * v1^2 = 1/2 * 4m * v2^2

2. Simplifying the equation:
Let's simplify the equation by canceling out common terms:

m * v1^2 = 4m * v2^2

Now, divide both sides of the equation by m:

v1^2 = 4v2^2

3. Taking square roots:
To isolate the velocities, we take the square root of both sides:

√(v1^2) = √(4v2^2)

Simplifying further:

v1 = 2v2

4. Ratio of velocities:
The ratio of the velocities can be written as:

v1 : v2 = 2 : 1

Therefore, the correct answer is option 'B' - 2:1.

Answer

K.e =1/2 mv^2
1/2mv^2 : 1/2(4m)v^2
v^2 : 4 v^2
1:4

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