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If x = a(cosx+xsinx), y = a(sinx - xcosx), find d^2 y/dx^2
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If x = a(cosx+xsinx), y = a(sinx - xcosx), find d^2 y/dx^2
Given: x = a(cosx xsinx), y = a(sinx - xcosx)

To find: d^2 y/dx^2

Solution:

Step 1: Find dy/dx

Given, y = a(sinx - xcosx)

Differentiating both sides w.r.t x, we get

dy/dx = a(cosx - cosx + xsinx) = axsinx

Step 2: Find d^2 y/dx^2

Differentiating dy/dx w.r.t x, we get

d^2 y/dx^2 = a(cosx + cosx + xcosx) = 2acosx + axcosx

Therefore, d^2 y/dx^2 = 2acosx + axcosx is the required second derivative of y w.r.t x.

Final Answer: d^2 y/dx^2 = 2acosx + axcosx
Community Answer
If x = a(cosx+xsinx), y = a(sinx - xcosx), find d^2 y/dx^2
Sec^3 x/ax
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If x = a(cosx+xsinx), y = a(sinx - xcosx), find d^2 y/dx^2
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