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How many different halides with molecular formula C7H15CI upon reduction with (C6H5)3SnH can give 2,4-dimethyl pentane?
    Correct answer is '4'. Can you explain this answer?
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    How many different halides with molecular formula C7H15CI upon reducti...
    Solution:

    Reduction of C7H15CI with (C6H5)3SnH gives 2,4-dimethyl pentane.

    To find the number of different halides with a molecular formula of C7H15CI that can give 2,4-dimethyl pentane, we need to analyze the structure of C7H15CI.

    The molecular formula C7H15CI suggests that the compound is a halide of an alkyl group with seven carbon atoms. Since the product obtained upon reduction is 2,4-dimethyl pentane, we can deduce that the halide must contain a 2-methyl and a 4-methyl group.

    We can represent the halide as follows:

    CH3-CH(CH3)-CH2-CH2-CH2-CH2-CI

    To obtain 2,4-dimethyl pentane upon reduction, the halide must have the following features:

    - The halogen atom must be attached to the seventh carbon atom of the alkyl chain.
    - The halide must have a 2-methyl group attached to the second carbon atom of the chain.
    - The halide must have a 4-methyl group attached to the fourth carbon atom of the chain.

    Using the above criteria, we can enumerate the following four halides with molecular formula C7H15CI that can give 2,4-dimethyl pentane upon reduction:

    1. 2-methyl-4-(chloromethyl)hexane
    2. 4-methyl-2-(chloromethyl)hexane
    3. 2,4-dimethyl-1-chlorohexane
    4. 2,4-dimethyl-2-chlorohexane

    Hence, the correct answer is '4'.
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    4 is correct.
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