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A certain household consumes 250 units of electric energy in a House. The energy consumed in mega joule is:
  • a)
    900 MJ
  • b)
    750 MJ
  • c)
    2250 MJ
  • d)
    1750 MJ.
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A certain household consumes 250 units of electric energy in a House. ...
1 unit = 1 Kwh
1 kWh = 3.6x10⁶ J
So, 250 units = 250 * 3.6 * 10⁶  = 900 * 10⁶ J
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Most Upvoted Answer
A certain household consumes 250 units of electric energy in a House. ...
1 unit=1 kwh
= 3.6×10^6 j

then,
250unit=250×3.6×10^6= 900×10^6

10^6joule = 1mega joule
so,
900×10^6joule =900MJ(Ans).
Free Test
Community Answer
A certain household consumes 250 units of electric energy in a House. ...
Calculation:
To calculate the energy consumed in mega joules, we need to convert the units of electric energy from units to mega joules.

Given: Energy consumed = 250 units

Conversion factor:
1 unit = 3.6 mega joules

Formula:
Energy in mega joules = Energy in units × Conversion factor

Calculation:
Energy in mega joules = 250 units × 3.6 mega joules/unit
Energy in mega joules = 900 mega joules

Therefore, the energy consumed in mega joules is 900 MJ.

Explanation:
The given problem states that a certain household consumes 250 units of electric energy. To find the energy consumed in mega joules, we need to convert the units to mega joules using the conversion factor.

1 unit is equivalent to 3.6 mega joules. So, by multiplying the number of units (250) by the conversion factor (3.6), we can find the energy consumed in mega joules.

250 units × 3.6 mega joules/unit = 900 mega joules

Hence, the correct answer is option 'A': 900 MJ.
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A certain household consumes 250 units of electric energy in a House. The energy consumed in mega joule is:a)900 MJb)750 MJc)2250 MJd)1750 MJ.Correct answer is option 'A'. Can you explain this answer?
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