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the momentum of a body increases by 20% calculate the percent decrease in its K.E
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the momentum of a body increases by 20% calculate the percent decrease...
We know,
KE = 1/2 mv2

P = mv

Therefore, KE = 1/2 (mv)2/m = p2/(2m)

Considering the mass to be constant, if the momentum is increased by 20%, let the new momentum be,

P/ = P + 0.2P = 1.2P

The new kinetic energy is, KE/ = (P/)2/(2m)

=> KE/ = (1.12)[P2/(2m)] = 1.44KE

=> (KE/)/KE = 1.44

=> (KE/ - KE)/KE = 0.44

=> (KE/ - KE)/KE X 100% = 44%
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the momentum of a body increases by 20% calculate the percent decrease in its K.E Related: Work & Energy, Important Questions (with answers), Class 9, Science
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