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A mixture of two gases X and Y is enclosed at constant temperature.The relative molecular mass of X which is diatomic is 8 times that of Y which is monoatomic .What is the ratio of the rms speed of molecules of Y to that of molecules of X ? (A)2 (B)2√2 (C)4 (D)8?
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A mixture of two gases X and Y is enclosed at constant temperature.The...
Acc to me:-
rms speed=√(3RT/M)
so rmsY/rmsX=√(Mx/My). ( as 3RT is const)
and Mx=8M
so rmsY/rmsX=√8 =2√2 is B correct.
Is it alright?
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For certain substances such as ammonium chloride, nitrogen peroxide, phosphorus pentachloride, etc. the measured densities are found to be less than those calculatedfrom their molecular formula. The observed densities decrease towards a limit as thetemperature is raised. This is due to the splitting of the molecules into simpler ones. The process is reversible and is called thermal dissociation.Examples :With increase in the number of molecules, the volume increases (pressure remaining constant) and, in consequence, the density decreases. As the temperature rises, more and more dissociation takes place, and when practically complete dissociation occursthe density reaches its lowest limit.The extent of issociation, ice., the fraction of the total number of molecules which suffers dissociation is called the degree of dissociation. Gas density measurements can be used to determine the degree of dissociation. Let us take by general case where one molecule of a substance A splits up into n molecule of B on heating; i.e.,t = 0 at = teq a x nx Total no. of moles Observed molecular weight or molar mass of the mixtureQ.The K for the reaction is 640 mm at 775 K. The percentage dissociation of N2O4 at equilibrium pressure of 160 mm is

For certain substances such as ammonium chloride, nitrogen peroxide, phosphorus pentachloride, etc. the measured densities are found to be less than those calculatedfrom their molecular formula. The observed densities decrease towards a limit as thetemperature is raised. This is due to the splitting of the molecules into simpler ones. The process is reversible and is called thermal dissociation.Examples :With increase in the number of molecules, the volume increases (pressure remaining constant) and, in consequence, the density decreases. As the temperature rises, more and more dissociation takes place, and when practically complete dissociation occursthe density reaches its lowest limit.The extent of issociation, ice., the fraction of the total number of molecules which suffers dissociation is called the degree of dissociation. Gas density measurements can be used to determine the degree of dissociation. Let us take by general case where one molecule of a substance A splits up into n molecule of B on heating; i.e.,t = 0 at = teq a x nx Total no. of moles Observed molecular weight or molar mass of the mixtureQ.If the total mass of the mixture in the above case is 300 gm, the moles at C(g) present are.

For certain substances such as ammonium chloride, nitrogen peroxide, phosphorus pentachloride, etc. the measured densities are found to be less than those calculatedfrom their molecular formula. The observed densities decrease towards a limit as thetemperature is raised. This is due to the splitting of the molecules into simpler ones. The process is reversible and is called thermal dissociation.Examples :With increase in the number of molecules, the volume increases (pressure remaining constant) and, in consequence, the density decreases. As the temperature rises, more and more dissociation takes place, and when practically complete dissociation occursthe density reaches its lowest limit.The extent of issociation, ice., the fraction of the total number of molecules which suffers dissociation is called the degree of dissociation. Gas density measurements can be used to determine the degree of dissociation. Let us take by general case where one molecule of a substance A splits up into n molecule of B on heating; i.e.,t = 0 at = teq a x nx Total no. of moles Observed molecular weight or molar mass of the mixtureQ.A sample of mixture of A(g), B(g) and C(g) under equilibrium has a mean molecular weight (observe d) is 80.The equilibrium is Find the degree of dissociation for A(g).

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A mixture of two gases X and Y is enclosed at constant temperature.The relative molecular mass of X which is diatomic is 8 times that of Y which is monoatomic .What is the ratio of the rms speed of molecules of Y to that of molecules of X ? (A)2 (B)2√2 (C)4 (D)8?
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A mixture of two gases X and Y is enclosed at constant temperature.The relative molecular mass of X which is diatomic is 8 times that of Y which is monoatomic .What is the ratio of the rms speed of molecules of Y to that of molecules of X ? (A)2 (B)2√2 (C)4 (D)8? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A mixture of two gases X and Y is enclosed at constant temperature.The relative molecular mass of X which is diatomic is 8 times that of Y which is monoatomic .What is the ratio of the rms speed of molecules of Y to that of molecules of X ? (A)2 (B)2√2 (C)4 (D)8? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A mixture of two gases X and Y is enclosed at constant temperature.The relative molecular mass of X which is diatomic is 8 times that of Y which is monoatomic .What is the ratio of the rms speed of molecules of Y to that of molecules of X ? (A)2 (B)2√2 (C)4 (D)8?.
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