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Consider a family of straight lines (x + y) + λ(2x - y + 1) = 0. Find the equation of the straight line belonging to this family that is farthest from (1, -3)a)15y − 6x − 7 = 0b)6x +15y - 7 = 0c)5x + 2y +1 = 0d)5x - 2y +1 = 0Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Consider a family of straight lines (x + y) + λ(2x - y + 1) = 0. Find the equation of the straight line belonging to this family that is farthest from (1, -3)a)15y − 6x − 7 = 0b)6x +15y - 7 = 0c)5x + 2y +1 = 0d)5x - 2y +1 = 0Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a family of straight lines (x + y) + λ(2x - y + 1) = 0. Find the equation of the straight line belonging to this family that is farthest from (1, -3)a)15y − 6x − 7 = 0b)6x +15y - 7 = 0c)5x + 2y +1 = 0d)5x - 2y +1 = 0Correct answer is option 'A'. Can you explain this answer?.

Solutions for Consider a family of straight lines (x + y) + λ(2x - y + 1) = 0. Find the equation of the straight line belonging to this family that is farthest from (1, -3)a)15y − 6x − 7 = 0b)6x +15y - 7 = 0c)5x + 2y +1 = 0d)5x - 2y +1 = 0Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

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