The volume of a drop of water is 0.0018ml then the number of water molecules present in two drops of water at room temprature is?

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The volume of a drop of water is 0.0018ml then the number of water molecules present in two drops of water at room temprature is?

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The volume of a drop of water is 0.0018ml then the number of water mol...

At RT i.e. 25 C, the density of water is 1 g/L.

Mass of water = Density x volume = 1 g/L x 0.0018 x 10-3 L = 1.8 x 10-3 g

18 g water = 1 mole

1mole water contains 6.023 x 1023 molecules of water

So, 18 g water cotains 6.023 x 1023 molecules of water

Then, 1.8 x 10-3 g water contains 1.8 x 10-3 x 6.023 x 1023 / 18 g = 6.023 x 1019 molecules of water

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