According to me....2,4,8,16,32,64,128,256,512... is the g.p series...which has common ratio aas 2..and last term is 512...then 5th term is 32....HOPE U GOT IT.

Given Information:
- First term (a) = 2
- Common ratio (r) = 2
- Last term (n) = 512

Formula for nth term of a GP:
The nth term of a geometric progression (GP) can be calculated using the formula:
an = a * r^(n-1)

Calculation of the 5th Term:
To find the 5th term (a5), we can substitute the given values into the formula:
a5 = a * r^(5-1)

Step 1: Calculate the value of r^(5-1):
r^(5-1) = r^4 = 2^4 = 16

Step 2: Substitute the values into the formula:
a5 = 2 * 16 = 32

Therefore, the 5th term of the GP is 32.

Explanation:
A geometric progression (GP) is a sequence of numbers where each term is found by multiplying the previous term by a fixed, non-zero number called the common ratio (r).

In this case, we are given that the first term (a) is 2 and the common ratio (r) is 2. We need to find the 5th term (a5) of the GP.

Using the formula for the nth term of a GP, we substitute the given values:
an = a * r^(n-1)

Substituting a = 2 and r = 2, we have:
a5 = 2 * 2^(5-1)

Simplifying the exponent, we get:
a5 = 2 * 2^4

Evaluating 2^4, we find that it is equal to 16:
a5 = 2 * 16

Multiplying 2 by 16, we get the value of the 5th term:
a5 = 32

Therefore, the 5th term of the given GP is 32.

The G.P is 2,4,8,16,....512.
a=2
r=2
IT IS A INCREASING GP
SO. an=a.r^(n-1)=2.2^(5-1)=32