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By selling two bicycles,a dealer neither earns profit nor earn loss.if he sold one bicycle at 15% profit and other at 9% loss and he bought them at rs 4320 then find cost price of each bicycle?
Most Upvoted Answer
By selling two bicycles,a dealer neither earns profit nor earn loss.if...
Let the cost of the bicycle with 9% loss be x.
Then the cost of another bicycle with 15 % profit will be (4320 - x).
Given that,
15% of (4320 - x) = 9% of x
= 15/100 × (4320 - x) = 9/100 × x (Cancel out 100 on both sides and cancel out 15 and 9 by coommon factor 3)
= 5 × 4320 - 5x = 3x
= 5 × 4320 = 3x + 5x
= 5 × 4320 = 8x
= x = ( 5 × 4320 ) / 8
= 5 × 540
= 2700
x = 2700
Now if the cost of 1 bicycle is Rs. 2700 the cost of another bicycle will be,
4320 - 2700 = 1620
Therefore , the cost of another bicycle is Rs. 1620

Check the answer :
15% of 1620 = 9% of 2700
= 15/100 × 1620 = 9/100 × 2700
= 243 = 243
Therefore , the answer is correct....
Community Answer
By selling two bicycles,a dealer neither earns profit nor earn loss.if...
Given information:
- The dealer sells two bicycles.
- The dealer neither earns a profit nor incurs a loss.
- One bicycle is sold at a 15% profit.
- The other bicycle is sold at a 9% loss.
- The cost price of both bicycles combined is Rs 4320.

To find:
- The cost price of each bicycle.

Solution:

Let's assume the cost price of the first bicycle is x and the cost price of the second bicycle is y.

Equations:
1. Selling price of the first bicycle = Cost price of the first bicycle + 15% profit
2. Selling price of the second bicycle = Cost price of the second bicycle - 9% loss
3. Cost price of both bicycles = x + y = Rs 4320

Calculating the selling prices:
- Selling price of the first bicycle = x + (15/100)x = 1.15x
- Selling price of the second bicycle = y - (9/100)y = 0.91y

Since the dealer neither earns a profit nor incurs a loss, the total selling price should be equal to the total cost price.

Equation:
1.15x + 0.91y = x + y

Rearranging the equation:
0.15x - 0.09y = 0

Simplifying further:
15x - 9y = 0

We also know that x + y = 4320. We can solve these two equations simultaneously to find the values of x and y.

Solving the equations:
1. 15x - 9y = 0
2. x + y = 4320

Multiplying equation 2 by 9 and subtracting it from equation 1:
15x - 9y - (9x + 9y) = 0 - 38880
6x = -38880

Dividing both sides by 6:
x = -38880/6
x = -6480

Substituting the value of x in the equation x + y = 4320:
-6480 + y = 4320
y = 4320 + 6480
y = 10800

Therefore, the cost price of the first bicycle is Rs 6480 and the cost price of the second bicycle is Rs 10800.

Conclusion:
The cost price of the first bicycle is Rs 6480 and the cost price of the second bicycle is Rs 10800.
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By selling two bicycles,a dealer neither earns profit nor earn loss.if he sold one bicycle at 15% profit and other at 9% loss and he bought them at rs 4320 then find cost price of each bicycle?
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