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how many gram atom of magnesium is present in 1 amu of magnesium
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how many gram atom of magnesium is present in 1 amu of magnesium
Gram Atom of Magnesium

A gram atom of magnesium refers to the atomic weight of magnesium in grams. It is also referred to as a mole of magnesium. The atomic weight of magnesium is 24.31 g/mol. Therefore, one gram atom of magnesium is equal to 24.31 grams of magnesium.

1 AMU of Magnesium

An atomic mass unit (AMU) is a unit of mass used to express atomic and molecular weights. One AMU is equal to one-twelfth of the mass of an atom of carbon-12, which is approximately 1.66 x 10^-24 grams. The atomic mass of magnesium is 24.31 AMU.

Calculation of Gram Atom of Magnesium in 1 AMU

Using the atomic mass of magnesium and the Avogadro's number, one can calculate the number of atoms of magnesium in one gram atom of magnesium and one AMU of magnesium.

- Avogadro's number: 6.022 x 10^23
- Atomic mass of magnesium: 24.31 AMU

To calculate the number of atoms in one gram atom of magnesium:

- 1 mole of magnesium = 24.31 g
- 1 mole of magnesium = 6.022 x 10^23 atoms (Avogadro's number)
- 24.31 g of magnesium = 6.022 x 10^23 atoms
- 1 gram atom of magnesium = 6.022 x 10^23 atoms

Therefore, one gram atom of magnesium contains 6.022 x 10^23 atoms of magnesium.

To calculate the number of atoms in 1 AMU of magnesium:

- 1 AMU of magnesium = 24.31/12 = 2.026 g/mol (mass of one magnesium atom in grams)
- 1 AMU of magnesium = 2.026 g/mol
- 1 AMU of magnesium = 2.026/24.31 moles
- 1 AMU of magnesium = 8.33 x 10^-2 moles
- Number of atoms in 1 AMU of magnesium = 8.33 x 10^-2 moles x 6.022 x 10^23 atoms/mole
- Number of atoms in 1 AMU of magnesium = 5.01 x 10^22 atoms

Therefore, one AMU of magnesium contains 5.01 x 10^22 atoms of magnesium.
Community Answer
how many gram atom of magnesium is present in 1 amu of magnesium
0.069×10ⁿ-24
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