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A hydrocarbon X (C7H14) on ozonolysis followed by work-up with Zn- H2O gives C6H12O as one of the product which on subsequent treatment with KOH/I2 gives yellow precipitate and salt of a chiral acid. Hence, X could be
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A hydrocarbon X (C7H14) on ozonolysis followed by work-up with Zn- H2O...
Ozonolysis of X gives C6H12O which has one carbon less than X. Hence, X must contain double bond at terminal carbon.
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A hydrocarbon X (C7H14) on ozonolysis followed by work-up with Zn- H2Ogives C6H12Oas one of the product which on subsequent treatment with KOH/I2 gives yellow precipitate and salt of a chiral acid. Hence, X could bea)b)c)d)Correct answer is option 'C'. Can you explain this answer?
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A hydrocarbon X (C7H14) on ozonolysis followed by work-up with Zn- H2Ogives C6H12Oas one of the product which on subsequent treatment with KOH/I2 gives yellow precipitate and salt of a chiral acid. Hence, X could bea)b)c)d)Correct answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A hydrocarbon X (C7H14) on ozonolysis followed by work-up with Zn- H2Ogives C6H12Oas one of the product which on subsequent treatment with KOH/I2 gives yellow precipitate and salt of a chiral acid. Hence, X could bea)b)c)d)Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A hydrocarbon X (C7H14) on ozonolysis followed by work-up with Zn- H2Ogives C6H12Oas one of the product which on subsequent treatment with KOH/I2 gives yellow precipitate and salt of a chiral acid. Hence, X could bea)b)c)d)Correct answer is option 'C'. Can you explain this answer?.
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