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an object of mass 10 kg is made to fall freely from a height of 10m .complete the table
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an object of mass 10 kg is made to fall freely from a height of 10m .c...
Final velocity of the body when it reaches the ground (100 cm =1 m)
v^2 = u^2 - 2as = 0 - {2*(-10)*1} = 20
So velocity just as it reaches the ground = (Square root of 20) m/s
Kinetic energy = 1/2*m*v^2 = 1/2*10*20 = 100 J
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an object of mass 10 kg is made to fall freely from a height of 10m .c...
Introduction
When an object is dropped from a height, it undergoes free fall, converting its potential energy into kinetic energy. Understanding this process illustrates the Law of Conservation of Energy, which states that energy cannot be created or destroyed but only transformed from one form to another.
Potential Energy (PE)
- The potential energy of an object at height (h) is given by the formula:
- PE = m * g * h
- Where:
- m = mass (10 kg)
- g = acceleration due to gravity (approximately 9.81 m/s²)
- h = height (10 m)
- Calculating Potential Energy:
- PE = 10 kg * 9.81 m/s² * 10 m = 981 Joules
Kinetic Energy (KE)
- As the object falls, its potential energy converts to kinetic energy. The kinetic energy of an object in motion is given by the formula:
- KE = 0.5 * m * v²
- Where:
- v = final velocity just before impact
- Calculating Final Velocity:
- Using the equation of motion: v² = u² + 2gh (u = initial velocity = 0):
- v² = 0 + 2 * 9.81 m/s² * 10 m = 196.2
- v = √196.2 ≈ 14 m/s
- Calculating Kinetic Energy:
- KE = 0.5 * 10 kg * (14 m/s)² = 980 Joules
Conservation of Energy
- Energy Transformation:
- At the height of 10 m:
- Potential Energy = 981 Joules
- Kinetic Energy = 0 Joules
- Just before impact:
- Potential Energy = 0 Joules
- Kinetic Energy ≈ 980 Joules
- Conclusion:
- The total energy remains constant:
- Initial PE = Final KE (approximately).
- This demonstrates the Law of Conservation of Energy in action.
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