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Two identical piano wires kept under the same tension T have a fundamental frequency of 600 Hz. The fractional increase in the tension of one of the wires which will lead to occurrence of 6 beats/s when both the wires oscillate together would be [2011M]
  • a)
    0.02
  • b)
    0.03
  • c)
    0.04
  • d)
    0.01
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Two identical piano wires kept under the same tension T have a fundame...
For fundamental mode,
Taking logarithm on both sides, we get
Differentiating both sides, we get
(as  and μ are constants)
Here df = 6            
f = 600 Hz
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Two identical piano wires kept under the same tension T have a fundamental frequency of 600 Hz. The fractional increase in the tension of one of the wires which will lead to occurrence of 6 beats/s when both the wires oscillate together would be [2011M]a)0.02b)0.03c)0.04d)0.01Correct answer is option 'A'. Can you explain this answer? for NEET 2026 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two identical piano wires kept under the same tension T have a fundamental frequency of 600 Hz. The fractional increase in the tension of one of the wires which will lead to occurrence of 6 beats/s when both the wires oscillate together would be [2011M]a)0.02b)0.03c)0.04d)0.01Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two identical piano wires kept under the same tension T have a fundamental frequency of 600 Hz. The fractional increase in the tension of one of the wires which will lead to occurrence of 6 beats/s when both the wires oscillate together would be [2011M]a)0.02b)0.03c)0.04d)0.01Correct answer is option 'A'. Can you explain this answer?.
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