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If x1 and x2 are the two values of x satisfying the equation 7^(2(x)^2) - 2(7^(x)^2 +12x) +7^(2x +24) =0 then find x1+ x2?
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If x1 and x2 are the two values of x satisfying the equation 7^(2(x)^2...
Solving the given equation using substitution:

Let a = 7^(x^2)

Then the equation becomes a^2 - 2(a*7^x*sqrt(3x)) + 7^(24) = 0

Using quadratic formula, we get:

a = [2(7^x*sqrt(3x)) ± sqrt(4(7^(2x)*3x) - 4(7^24))]/2

a = 7^x*sqrt(3x) ± sqrt(7^(2x)*3x - 7^24)

Substituting back to find x1 and x2:

Since a = 7^(x^2), we can substitute back to get:

7^(x^2) = 7^x*sqrt(3x) + sqrt(7^(2x)*3x - 7^24) or 7^x*sqrt(3x) - sqrt(7^(2x)*3x - 7^24)

Taking the natural logarithm of both sides and simplifying, we get:

x^2 = x*log(7) + 1/2*log(3x) ± 1/2*log(7^(2x)*3x - 7^24)

This can be solved using numerical methods or graphing to find the solutions x1 and x2.

Final Answer:

The values of x1 and x2 depend on the exact form of the expression in the last equation, which is difficult to simplify further. Therefore, numerical methods or graphing must be used to find the solutions.
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If x1 and x2 are the two values of x satisfying the equation 7^(2(x)^2...
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If x1 and x2 are the two values of x satisfying the equation 7^(2(x)^2) - 2(7^(x)^2 +12x) +7^(2x +24) =0 then find x1+ x2?
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If x1 and x2 are the two values of x satisfying the equation 7^(2(x)^2) - 2(7^(x)^2 +12x) +7^(2x +24) =0 then find x1+ x2? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If x1 and x2 are the two values of x satisfying the equation 7^(2(x)^2) - 2(7^(x)^2 +12x) +7^(2x +24) =0 then find x1+ x2? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If x1 and x2 are the two values of x satisfying the equation 7^(2(x)^2) - 2(7^(x)^2 +12x) +7^(2x +24) =0 then find x1+ x2?.
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