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Hydrogen peroxide in aqueous solution decomposes on warming to give oxygen acc. To the equation , 2H2O2 (aq.) → 2H2O (l) + O2 (g) . Under conditions where 1 mole of gas occupies 24dm3. 100cm3 of xM solution of H2O2 produces 3dm3 of O2. The x is:
- a)2.5
- b)1
- c)0.5
- d)0.25
Correct answer is option 'A'. Can you explain this answer?
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Hydrogen peroxide in aqueous solution decomposes on warming to give ox...
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Decomposition of Hydrogen Peroxide
Hydrogen peroxide (H2O2) in aqueous solution decomposes on warming to give oxygen according to the equation: 2H2O2 (aq.) 2H2O (l) O2 (g).
Volume of Oxygen Produced
Under conditions where 1 mole of gas occupies 24 dm3, 100 cm3 of x M solution of H2O2 produces 3 dm3 of O2.
Determination of x
To determine the value of x, we need to use the following formula:
n = V/Vm
where n is the number of moles, V is the volume of gas produced, and Vm is the molar volume of gas at the given temperature and pressure (24 dm3/mol).
From the given data, we have:
n = 3/24 = 0.125 mol
We know that the balanced equation for the decomposition of hydrogen peroxide is:
2H2O2 (aq.) 2H2O (l) O2 (g)
Therefore, for every 2 moles of H2O2 that decompose, 1 mole of O2 is produced. Therefore, the number of moles of H2O2 that decompose to produce 0.125 mol of O2 is:
n(H2O2) = (2/1) x 0.125 = 0.25 mol
Finally, we can calculate the concentration of the H2O2 solution as follows:
x = n/V
where n is the number of moles of H2O2 and V is the volume of the solution in dm3.
From the given data, we have:
V = 100/1000 = 0.1 dm3
x = 0.25/0.1 = 2.5 M
Therefore, the correct answer is option A (2.5).
Hydrogen peroxide (H2O2) in aqueous solution decomposes on warming to give oxygen according to the equation: 2H2O2 (aq.) 2H2O (l) O2 (g).
Volume of Oxygen Produced
Under conditions where 1 mole of gas occupies 24 dm3, 100 cm3 of x M solution of H2O2 produces 3 dm3 of O2.
Determination of x
To determine the value of x, we need to use the following formula:
n = V/Vm
where n is the number of moles, V is the volume of gas produced, and Vm is the molar volume of gas at the given temperature and pressure (24 dm3/mol).
From the given data, we have:
n = 3/24 = 0.125 mol
We know that the balanced equation for the decomposition of hydrogen peroxide is:
2H2O2 (aq.) 2H2O (l) O2 (g)
Therefore, for every 2 moles of H2O2 that decompose, 1 mole of O2 is produced. Therefore, the number of moles of H2O2 that decompose to produce 0.125 mol of O2 is:
n(H2O2) = (2/1) x 0.125 = 0.25 mol
Finally, we can calculate the concentration of the H2O2 solution as follows:
x = n/V
where n is the number of moles of H2O2 and V is the volume of the solution in dm3.
From the given data, we have:
V = 100/1000 = 0.1 dm3
x = 0.25/0.1 = 2.5 M
Therefore, the correct answer is option A (2.5).
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Community Answer
Hydrogen peroxide in aqueous solution decomposes on warming to give ox...
3L of O2 is produced, no. of moles = 3/24 = 0.125mol
2 mol H2O2 react to produce 1 mol O2, therefore there must be 0.125*2 = 0.250mol of H2O2
Now, molarity = n/V
V = 100mL = 0.1L
Therefore, x = 0.25/0.1 = 2.5 M (option A)
2 mol H2O2 react to produce 1 mol O2, therefore there must be 0.125*2 = 0.250mol of H2O2
Now, molarity = n/V
V = 100mL = 0.1L
Therefore, x = 0.25/0.1 = 2.5 M (option A)
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Hydrogen peroxide in aqueous solution decomposes on warming to give oxygen acc. To the equation , 2H2O2 (aq.) → 2H2O (l) + O2 (g) . Under conditions where 1 mole of gas occupies 24dm3. 100cm3 of xM solution of H2O2 produces 3dm3 of O2. The x is:a)2.5b)1c)0.5d)0.25Correct answer is option 'A'. Can you explain this answer?
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