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1000 mL 1 M CuSO4 (aq) is electrolysed by 9.65 amp current for 100 sec using Pt-electrode. Which is incorrect statemenet? (1) Blue colour intensity decreases during electrolysis. (2) Blue colour intensity remains constant if Cu-electrode used. (3) pH of solution is 8 after electrolysis. (4) At anode O2 gas liberated during electrolysis?
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1000 mL 1 M CuSO4 (aq) is electrolysed by 9.65 amp current for 100 sec...
Electrolysis of CuSO4 (aq)


Experimental Conditions


  • 1000 mL of 1 M CuSO4 (aq) solution

  • 9.65 amp current for 100 sec

  • Pt-electrode used



Observations


  • Blue colour intensity decreases during electrolysis

  • pH of solution is 8 after electrolysis

  • O2 gas liberated at the anode during electrolysis



Explanation

The blue colour of CuSO4 solution is due to the presence of Cu2+ ions. During electrolysis, Cu2+ ions are reduced to form Cu metal at the cathode. As a result, the concentration of Cu2+ ions in the solution decreases, leading to a decrease in the blue colour intensity of the solution. If a Cu-electrode were used instead of a Pt-electrode, Cu2+ ions would be reduced at the electrode surface, leading to the formation of Cu metal. The blue colour intensity of the solution would remain constant in this case.

The reduction of Cu2+ ions at the cathode results in the release of H+ ions, which increases the pH of the solution. After electrolysis, the pH of the solution is 8, indicating that the solution has become slightly basic.

At the anode, water molecules are oxidized to form O2 gas and H+ ions. The H+ ions combine with the OH- ions present in the solution to form water molecules. Hence, the overall reaction at the anode is:

2H2O(l) → O2(g) + 4H+(aq) + 4e-
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1000 mL 1 M CuSO4 (aq) is electrolysed by 9.65 amp current for 100 sec...
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1000 mL 1 M CuSO4 (aq) is electrolysed by 9.65 amp current for 100 sec using Pt-electrode. Which is incorrect statemenet? (1) Blue colour intensity decreases during electrolysis. (2) Blue colour intensity remains constant if Cu-electrode used. (3) pH of solution is 8 after electrolysis. (4) At anode O2 gas liberated during electrolysis?
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