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Charge through a cross-section of a conductor is given by Q = 5t^2 - 2t coulomb. Find the average current through the conductor in the interval t1 = 2 s to t2 = 4 s.Answer is 28 A....Is there any physics expert who will able to tell me how to solve this....!!
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Charge through a cross-section of a conductor is given by Q = 5t^2 - 2...
Calculation of Average Current in a Conductor

Given: Charge through the conductor, Q = 5t^2 - 2t coulomb

To find: The average current through the conductor in the time interval t1 = 2 s to t2 = 4 s.

Formula: The average current (I) is defined as the total charge (Q) passing through a conductor in a time interval (t) divided by the time interval. Mathematically, it can be expressed as:

I = ΔQ/Δt

where ΔQ is the change in charge and Δt is the change in time.

Solution:

Step 1: Calculate the charge passing through the conductor in the time interval from t1 = 2 s to t2 = 4 s.

Substituting t1 = 2 s and t2 = 4 s in the given equation, we get:

Q2 - Q1 = (5t2^2 - 2t2) - (5t1^2 - 2t1)
Q2 - Q1 = (5(4)^2 - 2(4)) - (5(2)^2 - 2(2))
Q2 - Q1 = (80 - 8) - (20 - 4)
Q2 - Q1 = 56 C

Therefore, the charge passing through the conductor in the time interval from t1 = 2 s to t2 = 4 s is 56 C.

Step 2: Calculate the time interval (Δt) between t1 = 2 s and t2 = 4 s.

Δt = t2 - t1
Δt = 4 s - 2 s
Δt = 2 s

Therefore, the time interval between t1 = 2 s and t2 = 4 s is 2 s.

Step 3: Calculate the average current (I) through the conductor.

I = ΔQ/Δt
I = 56 C/2 s
I = 28 A

Therefore, the average current through the conductor in the time interval from t1 = 2 s to t2 = 4 s is 28 A.

Conclusion:

Hence, the average current through the conductor in the time interval from t1 = 2 s to t2 = 4 s is 28 A.
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Charge through a cross-section of a conductor is given by Q = 5t^2 - 2t coulomb. Find the average current through the conductor in the interval t1 = 2 s to t2 = 4 s.Answer is 28 A....Is there any physics expert who will able to tell me how to solve this....!!
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