Class 11 Exam > Class 11 Questions > Q.(Sin¤ icos¤)^2 (1 icot¤)^3/(1 i tan¤)^4?
Start Learning for Free
Q.(Sin¤ icos¤)^2 (1 icot¤)^3/(1 i tan¤)^4?
Most Upvoted Answer
Q.(Sin¤ icos¤)^2 (1 icot¤)^3/(1 i tan¤)^4?
Solution:
Given expression is (Sin¤ icos¤)^2 (1 icot¤)^3/(1 i tan¤)^4
Step 1: Simplify the numerator
First, we will simplify the numerator
(Sin¤ icos¤)^2 = [(Sin¤)^2 (cos¤)^2] = (Sin¤)^2 (1 - Sin^2¤) = (Sin^3¤ - Sin¤)
(1 icot¤)^3 = (1 icot¤)^2 (1 icot¤) = (1 - 2icot¤ - icot^2¤) (1 icot¤) = (1 - icot¤ - icot^2¤) = (1 - cos¤ - isin¤)
Now, we can substitute these values in the expression:
(Sin^3¤ - Sin¤) [(1 - cos¤ - isin¤)]^3
Step 2: Simplify the denominator
Next, we will simplify the denominator
(1 i tan¤)^4 = (1 + itan¤)^4 (1 - itan¤)^4 = [(1 - tan^2¤) + 2itan¤]^4 [(1 - tan^2¤) - 2itan¤]^4 = [1 - 4tan^2¤ - 6itan¤ - 4tan^4¤ - i8tan^3¤]^4
Step 3: Combine the terms
Now we can substitute the above values in the expression and simplify:
(Sin^3¤ - Sin¤) [(1 - cos¤ - isin¤)]^3 / [1 - 4tan^2¤ - 6itan¤ - 4tan^4¤ - i8tan^3¤]^4
Step 4: Further simplification
Finally, we can simplify the above expression by multiplying the numerator and the denominator by the conjugate of the denominator:
(Sin^3¤ - Sin¤) [(1 - cos¤ - isin¤)]^3 [(1 + 4tan^2¤ + 6itan¤ + 4tan^4¤ + i8tan^3¤)]^4 / [(1 + 4tan^2¤)^8 + 64tan^6¤]^2
Therefore, the simplified expression is (Sin^3¤ - Sin¤) [(1 - cos¤ - isin¤)]^3 [(1 + 4tan^2¤ + 6itan¤ + 4tan^4¤ + i8tan^3¤)]^4 / [(1 + 4tan^2¤)^8 + 64tan^6¤]^2
Community Answer
Q.(Sin¤ icos¤)^2 (1 icot¤)^3/(1 i tan¤)^4?
I am a med student
Attention Class 11 Students!
To make sure you are not studying endlessly, EduRev has designed Class 11 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 11.
|
Explore Courses for Class 11 exam
|
|
Top Courses for Class 11View all
Q.(Sin¤ icos¤)^2 (1 icot¤)^3/(1 i tan¤)^4?
Question Description
Q.(Sin¤ icos¤)^2 (1 icot¤)^3/(1 i tan¤)^4? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Q.(Sin¤ icos¤)^2 (1 icot¤)^3/(1 i tan¤)^4? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Q.(Sin¤ icos¤)^2 (1 icot¤)^3/(1 i tan¤)^4?.
Q.(Sin¤ icos¤)^2 (1 icot¤)^3/(1 i tan¤)^4? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Q.(Sin¤ icos¤)^2 (1 icot¤)^3/(1 i tan¤)^4? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Q.(Sin¤ icos¤)^2 (1 icot¤)^3/(1 i tan¤)^4?.
Solutions for Q.(Sin¤ icos¤)^2 (1 icot¤)^3/(1 i tan¤)^4? in English & in Hindi are available as part of our courses for Class 11.
Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.
Here you can find the meaning of Q.(Sin¤ icos¤)^2 (1 icot¤)^3/(1 i tan¤)^4? defined & explained in the simplest way possible. Besides giving the explanation of
Q.(Sin¤ icos¤)^2 (1 icot¤)^3/(1 i tan¤)^4?, a detailed solution for Q.(Sin¤ icos¤)^2 (1 icot¤)^3/(1 i tan¤)^4? has been provided alongside types of Q.(Sin¤ icos¤)^2 (1 icot¤)^3/(1 i tan¤)^4? theory, EduRev gives you an
ample number of questions to practice Q.(Sin¤ icos¤)^2 (1 icot¤)^3/(1 i tan¤)^4? tests, examples and also practice Class 11 tests.
|
|
Explore Courses for Class 11 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup