A solid has a structure in which W-atoms are located at the corners of...
Given information:
- W-atoms are present at the corners of a cubic lattice
- OF-atoms are present at the centre of edges
- Na atom is present at the centre of the cube
To find:
The formula of the compound
Solution:
1. Determine the number of Na atoms in the unit cell:
- Na atom is present at the centre of the cube
- Therefore, only 1 Na atom is present in the unit cell
2. Determine the number of W atoms in the unit cell:
- W atoms are present at the corners of the cubic lattice
- Each corner is shared by 8 unit cells, so each W atom will contribute 1/8th to the unit cell
- Therefore, the total number of W atoms in the unit cell = 8 x 1/8 = 1
3. Determine the number of O atoms in the unit cell:
- O atoms are present at the centre of edges
- Each edge is shared by 4 unit cells, so each O atom will contribute 1/4th to the unit cell
- There are 12 edges in a cubic lattice, so the total number of O atoms in the unit cell = 12 x 1/4 = 3
4. Determine the ratio of Na, W, and O atoms:
- From the above calculations, we have 1 Na atom, 1 W atom, and 3 O atoms in the unit cell
- To get the simplest ratio, we need to divide by the smallest number (which is 1 in this case)
- Therefore, the ratio of Na:W:O = 1:1:3
5. Write the formula of the compound:
- The formula of the compound is given by the ratio of the atoms present in the unit cell
- From step 4, we have the ratio of Na:W:O = 1:1:3
- Therefore, the formula of the compound is NaWO3
Hence, the correct answer is option D (NaWO3).
A solid has a structure in which W-atoms are located at the corners of...
As in a cubic unit cell ,as we know that if particle at center it will constitute 1atom.Hence Na
Then particle if present at center of edge in a cubic unit cell each atom will constitute 1/4th part .So as there are 12 edges =)(O)atom will be =)1/4×12=3. similarly,for corners 1/8th part of an atom at each corner so W atom will be =)1/8×8=1 as there are 8 corners .
Hence,the answer is
NaWO3