A boy throws ball upward with velocity 9.8 metre per second how high d...
Calculating the Maximum Height of a Ball Thrown Upward
When a ball is thrown upward, its initial velocity is positive and its acceleration due to gravity is negative. The acceleration due to gravity is a constant value of -9.8 m/s², and it causes the ball to slow down as it moves upward until it reaches its maximum height and begins to fall back down to the ground. Using the principles of kinematics, we can calculate the maximum height that the ball reaches.
Step 1: Determine the Initial Velocity of the Ball
The initial velocity of the ball is given as 9.8 m/s. Since the ball is thrown upward, we take the initial velocity as positive.
Step 2: Determine the Time it Takes for the Ball to Reach its Maximum Height
The time it takes for the ball to reach its maximum height can be calculated using the following kinematic equation:
vf = vi + at
where:
- vf = final velocity (0 m/s at maximum height)
- vi = initial velocity (9.8 m/s upward)
- a = acceleration due to gravity (-9.8 m/s²)
- t = time
Solving for t, we get:
t = (vf - vi) / a
Since the final velocity is zero at maximum height, we can simplify the equation to:
t = -vi / a
Substituting the values, we get:
t = -9.8 m/s / -9.8 m/s²
t = 1 second
Step 3: Calculate the Maximum Height of the Ball
The maximum height that the ball reaches can be calculated using the following kinematic equation:
Δy = vi * t + 1/2 * a * t²
where:
- Δy = change in height (maximum height - initial height)
- vi = initial velocity (9.8 m/s upward)
- a = acceleration due to gravity (-9.8 m/s²)
- t = time (1 second)
Substituting the values, we get:
Δy = 9.8 m/s * 1 second + 1/2 * -9.8 m/s² * (1 second)²
Δy = 4.9 meters
Step 4: Interpret the Result
The maximum height that the ball reaches is 4.9 meters. This means that the ball travels 4.9 meters upward from its initial height before it begins to fall back down to the ground. It also takes 1 second to reach this maximum height.