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in triangle ABC ,angle b is 90degree and bd is perpendicular bisector of ac. prove that angle ABD = angle ACB
Most Upvoted Answer
in triangle ABC ,angle b is 90degree and bd is perpendicular bisector ...
Since bd is perpendicular it forms triangle abd with half angle b that is 45 degree
then consider triangle bdc we have at b as 45 degrees and d as 90 degree then by angle sum property of triangle
we have
90+45+angle c=180
135+c=180
c=180-135=45 degrees
hence angle abd =angle acb
Community Answer
in triangle ABC ,angle b is 90degree and bd is perpendicular bisector ...
Since bd is perpendicular it forms triangle abd with half angle b that is 45 degree

then consider triangle bdc we have at b as 45 degrees and d as 90 degree then by angle sum property of triangle 

we have

90+45+angle c=180

135+c=180

c=180-135=45 degrees 

hence angle abd =angle acb
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in triangle ABC ,angle b is 90degree and bd is perpendicular bisector of ac. prove that angle ABD = angle ACB
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