State of Hybridisation of Xe in Cationic Part of Solid XeF6

State of Hybridisation

The state of hybridization of Xe in cationic part of solid XeF6 is sp3d2.

Explanation

- XeF6 is a compound that exists as a solid at room temperature and pressure. It is a powerful fluorinating agent and is used in many industrial processes.
- In XeF6, the xenon atom is surrounded by six fluorine atoms, and the molecule has an octahedral geometry.
- In solid XeF6, the fluorine atoms are arranged in a face-centered cubic lattice. Each xenon atom is surrounded by eight fluorine atoms, forming a distorted cube.
- The xenon atom in XeF6 undergoes sp3d2 hybridization. This means that the xenon atom uses one 5s, three 5p, and two 5d orbitals to form six sp3d2 hybrid orbitals.
- The six sp3d2 hybrid orbitals of the xenon atom are used to form six sigma bonds with the six fluorine atoms in XeF6. Each fluorine atom contributes one electron to the bond, resulting in a total of six sigma bonds.
- The remaining two 5p orbitals of the xenon atom are used to form two pi bonds with two pairs of fluorine atoms. These pi bonds are formed by the overlap of the 5p orbitals of the xenon atom with the 2p orbitals of the fluorine atoms.
- The sp3d2 hybridization of the xenon atom in XeF6 is consistent with the octahedral geometry of the molecule and the distorted cube geometry of the solid.

Conclusion

In conclusion, the state of hybridization of Xe in the cationic part of solid XeF6 is sp3d2. This hybridization allows the xenon atom to form six sigma bonds and two pi bonds with the fluorine atoms, resulting in the octahedral geometry of the molecule and the distorted cube geometry of the solid.

Draw the structure of XeF6 , it contains 6 bond pairs and one lone pair.Hence, hybri.. is sp3d2