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The potential energy of an electron in the second Bohr's orbit of the he±
  • a)
    - 54.4 eV
  • b)
    -27.2 eV
  • c)
    -108.8 eV
  • d)
    -13.6 eV
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The potential energy of an electron in the second Bohr's orbit of ...
Using the formula E=−13.6z2/n2eVE=−13.6z2/n2eV Where z is atomic no. And n is the no of orbitSo energy of second orbit of he would be −13.6×2×2/2×2=−13.6eV
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Most Upvoted Answer
The potential energy of an electron in the second Bohr's orbit of ...
The potential energy of an electron in the second Bohr's orbit of the hydrogen atom can be calculated using the formula:

E = -13.6 eV / n^2

Where E is the energy, -13.6 eV is the ionization energy of hydrogen, and n is the principal quantum number.

For the second Bohr's orbit, n = 2. Substituting the values into the formula:

E = -13.6 eV / (2^2)
E = -13.6 eV / 4
E = -3.4 eV

Therefore, the potential energy of an electron in the second Bohr's orbit of the hydrogen atom is -3.4 eV.
Community Answer
The potential energy of an electron in the second Bohr's orbit of ...
Answer for this question is -27.2 .in the question they ask P.E .....so we have to find the P.E...the formula is P.E =-2K.E
P.E =-2×Z2/n2 ×K
=-2×2×2/2×2×13.6
=-2×13.6
=-27.2 eV
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The potential energy of an electron in the second Bohr's orbit of the he±a)- 54.4 eVb)-27.2 eVc)-108.8 eVd)-13.6 eVCorrect answer is option 'D'. Can you explain this answer?
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