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If 8 bolts are emplaced in a clamp coupling with shaft diameter 80mm d, calculate the diameter of each bolt if coefficient of friction is 0.3 and torque transmitted is 4000N-m. Permissible tensile stress is 80N/mm².
- a)27mm
- b)25mm
- c)23mm
- d)21mm
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
If 8 bolts are emplaced in a clamp coupling with shaft diameter 80mm d...
Explanation: Ax80=2M/fdn.
Most Upvoted Answer
If 8 bolts are emplaced in a clamp coupling with shaft diameter 80mm d...
We can use the formula for torque transmitted through bolts in a clamp coupling:
T = (π/16) * d^3 * μ * n * σ
where:
T = torque transmitted (4000 N-m)
d = diameter of each bolt
μ = coefficient of friction (0.3)
n = number of bolts (8)
σ = permissible tensile stress (80 N/mm)
Rearranging the formula to solve for d, we get:
d = [(16 * T) / (π * μ * n * σ)]^(1/3)
Substituting the given values and solving, we get:
d = [(16 * 4000) / (π * 0.3 * 8 * 80)]^(1/3)
d = 23.6 mm (rounded to one decimal place)
Therefore, each bolt should have a diameter of approximately 23.6 mm.
T = (π/16) * d^3 * μ * n * σ
where:
T = torque transmitted (4000 N-m)
d = diameter of each bolt
μ = coefficient of friction (0.3)
n = number of bolts (8)
σ = permissible tensile stress (80 N/mm)
Rearranging the formula to solve for d, we get:
d = [(16 * T) / (π * μ * n * σ)]^(1/3)
Substituting the given values and solving, we get:
d = [(16 * 4000) / (π * 0.3 * 8 * 80)]^(1/3)
d = 23.6 mm (rounded to one decimal place)
Therefore, each bolt should have a diameter of approximately 23.6 mm.
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If 8 bolts are emplaced in a clamp coupling with shaft diameter 80mm d, calculate the diameter of each bolt if coefficient of friction is 0.3 and torque transmitted is 4000N-m. Permissible tensile stress is 80N/mm².a)27mmb)25mmc)23mmd)21mmCorrect answer is option 'A'. Can you explain this answer?
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