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What is Integration of" 2 log sec x" power of "e" ?
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What is Integration of" 2 log sec x" power of "e" ?
Integration of 2 log(secx)e


Integration is the process of finding the antiderivative of a function. The integration of 2 log(secx)e can be solved by using the substitution method.


Step 1: Use substitution


Let u = sec(x). Therefore, du/dx = sec(x)tan(x)

Using the identity sec2(x) - 1 = tan2(x), we get:

tan2(x) + 1 = sec2(x)

tan2(x) = sec2(x) - 1

tan2(x) = u2 - 1

tan(x)sec(x)dx = du


Step 2: Substitute the value of u and du


The given expression can now be written as:

2 log(u)e sec(x)tan(x)dx

2 log(u)e du


Step 3: Integrate the expression


Now we can integrate the expression:

2 ∫ log(u)e du

Using the power rule of integration:

2 [(u log(u)e) - ∫ u (1/e) du]

2 [(u log(u)e) - (u/e) + C]


Step 4: Substitute the value of u


Substituting the value of u = sec(x), we get:

2 [sec(x) log(sec(x))e - (sec(x)/e) + C]


Final Answer:

The integration of 2 log(secx)e is 2 [sec(x) log(sec(x))e - (sec(x)/e) + C].
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What is Integration of" 2 log sec x" power of "e" ?
It can be written as e to the power sec squared x and integration of e to power log sec'2 x will be integration of Sec'2x which is tanx +c
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What is Integration of" 2 log sec x" power of "e" ?
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