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In the keto-enol tautomerism of dicarbonyl compounds the enol form is preferred in contrast to the keto form, this is due to
- a)presence of carbonyl group on each side of -CH₂
- b)resonance stablization of enol form
- c)presence of methylene group
- d)rapid chemical exchange
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
In the keto-enol tautomerism of dicarbonyl compounds the enol form is ...
Explanation:
Keto-enol tautomerism is an equilibrium between the keto form and the enol form of a molecule. In dicarbonyl compounds, the enol form is preferred over the keto form. This is due to the resonance stabilization of the enol form.
Resonance stabilization of enol form:
The enol form has a double bond between the carbon and oxygen atoms (C=C-OH), which allows for resonance stabilization. The pi electrons of the double bond can move onto the oxygen atom, creating a negative charge on the oxygen and a positive charge on the carbon. This creates a resonance structure where the double bond moves onto the adjacent carbonyl group, which also has a negative charge on the oxygen and a positive charge on the carbon. The result is a delocalization of charge, which stabilizes the enol form.
Presence of carbonyl group on each side of -CH:
The presence of carbonyl groups on each side of the -CH group does not have a significant effect on the preference for the enol form.
Presence of methylene group:
The presence of a methylene group (CH2) does not have a significant effect on the preference for the enol form.
Rapid chemical exchange:
Rapid chemical exchange between the keto and enol forms is possible, but the preference for the enol form is due to its greater stability through resonance stabilization.
Therefore, the correct answer is option B, resonance stabilization of the enol form.
Keto-enol tautomerism is an equilibrium between the keto form and the enol form of a molecule. In dicarbonyl compounds, the enol form is preferred over the keto form. This is due to the resonance stabilization of the enol form.
Resonance stabilization of enol form:
The enol form has a double bond between the carbon and oxygen atoms (C=C-OH), which allows for resonance stabilization. The pi electrons of the double bond can move onto the oxygen atom, creating a negative charge on the oxygen and a positive charge on the carbon. This creates a resonance structure where the double bond moves onto the adjacent carbonyl group, which also has a negative charge on the oxygen and a positive charge on the carbon. The result is a delocalization of charge, which stabilizes the enol form.
Presence of carbonyl group on each side of -CH:
The presence of carbonyl groups on each side of the -CH group does not have a significant effect on the preference for the enol form.
Presence of methylene group:
The presence of a methylene group (CH2) does not have a significant effect on the preference for the enol form.
Rapid chemical exchange:
Rapid chemical exchange between the keto and enol forms is possible, but the preference for the enol form is due to its greater stability through resonance stabilization.
Therefore, the correct answer is option B, resonance stabilization of the enol form.
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In the keto-enol tautomerism of dicarbonyl compounds the enol form is ...
Yes due to resonance the enol form is more stable but only in aromatic compounds, than keto form
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In the keto-enol tautomerism of dicarbonyl compounds the enol form is preferred in contrast to the keto form, this is due toa)presence of carbonyl group on each side of -CH₂b)resonance stablization of enol formc)presence of methylene groupd)rapid chemical exchangeCorrect answer is option 'B'. Can you explain this answer?
Question Description
In the keto-enol tautomerism of dicarbonyl compounds the enol form is preferred in contrast to the keto form, this is due toa)presence of carbonyl group on each side of -CH₂b)resonance stablization of enol formc)presence of methylene groupd)rapid chemical exchangeCorrect answer is option 'B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In the keto-enol tautomerism of dicarbonyl compounds the enol form is preferred in contrast to the keto form, this is due toa)presence of carbonyl group on each side of -CH₂b)resonance stablization of enol formc)presence of methylene groupd)rapid chemical exchangeCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the keto-enol tautomerism of dicarbonyl compounds the enol form is preferred in contrast to the keto form, this is due toa)presence of carbonyl group on each side of -CH₂b)resonance stablization of enol formc)presence of methylene groupd)rapid chemical exchangeCorrect answer is option 'B'. Can you explain this answer?.
In the keto-enol tautomerism of dicarbonyl compounds the enol form is preferred in contrast to the keto form, this is due toa)presence of carbonyl group on each side of -CH₂b)resonance stablization of enol formc)presence of methylene groupd)rapid chemical exchangeCorrect answer is option 'B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In the keto-enol tautomerism of dicarbonyl compounds the enol form is preferred in contrast to the keto form, this is due toa)presence of carbonyl group on each side of -CH₂b)resonance stablization of enol formc)presence of methylene groupd)rapid chemical exchangeCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the keto-enol tautomerism of dicarbonyl compounds the enol form is preferred in contrast to the keto form, this is due toa)presence of carbonyl group on each side of -CH₂b)resonance stablization of enol formc)presence of methylene groupd)rapid chemical exchangeCorrect answer is option 'B'. Can you explain this answer?.
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In the keto-enol tautomerism of dicarbonyl compounds the enol form is preferred in contrast to the keto form, this is due toa)presence of carbonyl group on each side of -CH₂b)resonance stablization of enol formc)presence of methylene groupd)rapid chemical exchangeCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for In the keto-enol tautomerism of dicarbonyl compounds the enol form is preferred in contrast to the keto form, this is due toa)presence of carbonyl group on each side of -CH₂b)resonance stablization of enol formc)presence of methylene groupd)rapid chemical exchangeCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of In the keto-enol tautomerism of dicarbonyl compounds the enol form is preferred in contrast to the keto form, this is due toa)presence of carbonyl group on each side of -CH₂b)resonance stablization of enol formc)presence of methylene groupd)rapid chemical exchangeCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
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