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The shape of XeO2F2 molecule is
  • a)
    trigonal bipyramidal
  • b)
    square planar
  • c)
    tetrahedral
  • d)
    see-saw
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The shape of XeO2F2 molecule isa)trigonal bipyramidalb)square planarc)...
XeO2F2 has tr igonal bipyramidal geometry, due to presence of lone pair of electrons on equitorial position, its shape is see-saw.
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Most Upvoted Answer
The shape of XeO2F2 molecule isa)trigonal bipyramidalb)square planarc)...
Explanation:

The XeO2F2 molecule consists of xenon (Xe), oxygen (O), and fluorine (F) atoms. To determine the shape of the molecule, we need to consider the electron and molecular geometry.

Electron Geometry:
Xenon (Xe) has an electron configuration of [Kr]5s24d105p6, meaning it has 8 valence electrons. Oxygen (O) has a configuration of 1s22s22p4 and fluorine (F) has a configuration of 1s22s22p5.

To determine the electron geometry, we need to count all the valence electrons from the atoms present in the molecule. In this case, we have:
- Xenon (Xe): 8 valence electrons
- Oxygen (O): 6 valence electrons x 2 = 12 valence electrons
- Fluorine (F): 7 valence electrons x 2 = 14 valence electrons

Therefore, the total number of valence electrons is 8 + 12 + 14 = 34.

Molecular Geometry:
To determine the molecular geometry, we need to consider the number of bonding and non-bonding electron pairs around the central atom (Xe).

In the XeO2F2 molecule, there are 2 oxygen atoms bonded to the central xenon atom and 2 fluorine atoms bonded to the central xenon atom.

Using the valence electron count, we can distribute the electrons as follows:
- Xenon (Xe): 8 valence electrons
- Oxygen (O): 6 valence electrons x 2 = 12 valence electrons
- Fluorine (F): 7 valence electrons x 2 = 14 valence electrons

We can form single bonds between xenon and each oxygen and fluorine atom, which accounts for 2 x 2 = 4 electrons.

After bonding, we have 34 - 4 = 30 electrons remaining. These remaining electrons will be placed as non-bonding electron pairs on the oxygen and xenon atoms. Each oxygen atom can accommodate 6 electrons (2 in the lone pair and 4 in the bonding pair), while the xenon atom can accommodate 8 electrons (2 in the lone pair and 6 in the bonding pair).

Shape:
Based on the electron and molecular geometry, the XeO2F2 molecule has the shape of a "see-saw." This shape is characterized by four bonding pairs and one lone pair of electrons around the central atom. The four atoms bonded to the central xenon atom are not arranged symmetrically, resulting in the "see-saw" shape.

Therefore, the correct answer is option D: see-saw.
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The shape of XeO2F2 molecule isa)trigonal bipyramidalb)square planarc)tetrahedrald)see-sawCorrect answer is option 'D'. Can you explain this answer?
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