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when a car is traveling in a straight road.
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when a car is traveling in a straight road.
A car is travelling along a straight road at u =14 m/s
The distance from the point where the brakes are applied to the point where the car comes to rest is s = 49m
We know that
speed = distance / time
time = distance / speed = 49 / 14  = 3.5 seconds.
 
Thus, this car travells for t= 3.5 seconds.
During the course of applying the brakes and finally stopping the motion (v = 0 m/s)
The deceleration can be found using the below equation of motion:
 
v = u + at 
Where, v is final velocity (zero, as the car stops)
t is the time of travel (3.5 seconds, as calculated)
u is the initial velocity ( 14 m/s, as given)
 
Substituting the values,
0 = 14 + a (3.5)
a = -14 / 3.5
a = - 4 m/s2 
 
The negative symbol above symbolises that the car undergoes deceleation (gradual decrease in acceleration)
Thus, the deceleration of the car is - 4 m/s2 . 
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