Two capacitors of capacitances 5 micro farad and 10 micro farad are charged to 16 volts and 10 volts respectively. Find the common potential when they are connected in parallel?

Question

Answer

In parallel combination ,the common potential is given by,
V=V1C1+V2C2/C1+C2.
V=16×5×10^-6 + 10× 10× 10^-6/5×10^-6 + 10×10^-6.
V=10^-6(80+100)/15×10^-6.
V=180/15.
V=12...

Answer

Problem Statement

Two capacitors of capacitances 5 micro farad and 10 micro farad are charged to 16 volts and 10 volts respectively. Find the common potential when they are connected in parallel?

Solution

Step 1: Finding the charge on each capacitor

Charge on capacitor = capacitance x voltage

For 5 micro farad capacitor, charge = 5 x 10^-6 x 16 = 0.00008 C

For 10 micro farad capacitor, charge = 10 x 10^-6 x 10 = 0.0001 C

Step 2: Finding the total charge

Total charge = charge on capacitor 1 + charge on capacitor 2

Total charge = 0.00008 + 0.0001 = 0.00018 C

Step 3: Finding the equivalent capacitance

Equivalent capacitance = capacitance of capacitor 1 + capacitance of capacitor 2

Equivalent capacitance = 5 x 10^-6 + 10 x 10^-6 = 15 x 10^-6 = 15 micro farad

Step 4: Finding the common potential

Common potential = total charge / equivalent capacitance

Common potential = 0.00018 / 15 x 10^-6 = 12 volts

Therefore, the common potential when the capacitors are connected in parallel is 12 volts.

Explanation

When two capacitors are connected in parallel, the equivalent capacitance is the sum of the individual capacitances. The charge on each capacitor is equal to its capacitance multiplied by the voltage across it. The total charge on both capacitors is the sum of their individual charges. The common potential is the total charge divided by the equivalent capacitance.

Answer

Answer

Q1= C1* V1 Q2=C2*V2
= 80 micro F. =100 micro F
Q total = 180 micro C
V total = Q total/C total
= 180/15
=12V

hope this will help.....

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