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An organic compound A (C3H9N), reacts with Hinsberg's reagent and the product so formed is not soluble in alkali, but soluble in ether. Identify A?
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An organic compound A (C3H9N), reacts with Hinsberg's reagent and the ...
Identification of Compound A:
- Compound A is a tertiary amine (C3H9N) based on the given molecular formula.
- When Compound A reacts with Hinsberg's reagent, it forms an insoluble product which indicates the presence of a tertiary amine group.
- The product formed is not soluble in alkali, confirming the absence of acidic hydrogen atoms in Compound A.
- The product is soluble in ether, suggesting that it is a non-polar compound.

Explanation:
- Tertiary amines do not react with Hinsberg's reagent to form a soluble product because the resulting compound is a tertiary amide which is insoluble.
- The lack of acidic hydrogen atoms in Compound A prevents it from forming water-soluble salts with alkali.
- Being non-polar, the product of the reaction is soluble in ether, which is a non-polar solvent.
Therefore, based on the given information, Compound A can be identified as a tertiary amine (C3H9N) which forms an insoluble product with Hinsberg's reagent, is not soluble in alkali, and is soluble in ether.
Community Answer
An organic compound A (C3H9N), reacts with Hinsberg's reagent and the ...
The compound with molecular formula C3H9N is a secondary amine . when it react with Hinsberg reagent ,the product obtained is soluble in ether
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An organic compound A (C3H9N), reacts with Hinsberg's reagent and the product so formed is not soluble in alkali, but soluble in ether. Identify A?
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