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A plastic object of mass 0.5 kg is immersed in water.The buoyant force acting on the object if it displaces 0.5g of water?
Verified Answer
A plastic object of mass 0.5 kg is immersed in water.The buoyant force...
Mass = 50g
volume = 20cm^3
density = mass/volume = 50/20 = 2.5 g/cm^3
density of water = 1 g/cm^3

Since the density of the substance is greater than the density of water, it will sink in water.

The volume of water displaced = 20 cm^3
mass of water displaced = volume�density = 20�1 = 20g
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A plastic object of mass 0.5 kg is immersed in water.The buoyant force...
Introduction
When a plastic object is immersed in water, it experiences a buoyant force due to the displacement of water. This buoyant force is a result of Archimedes' principle, which states that the buoyant force acting on an object submerged in a fluid is equal to the weight of the fluid displaced by the object.

Explanation
The buoyant force acting on the plastic object can be calculated using the following formula:

Fb = ρwater * V * g

Where:
- Fb is the buoyant force
- ρwater is the density of water
- V is the volume of water displaced by the object
- g is the acceleration due to gravity

In this case, the plastic object displaces 0.5g of water. To calculate the volume of water displaced, we need to use the formula:

V = mwater / ρwater

Where:
- V is the volume of water displaced
- mwater is the mass of water displaced
- ρwater is the density of water

Since the mass of water displaced is given as 0.5g, we can substitute these values into the equation to find the volume of water displaced.

V = 0.5g / ρwater

Now, we can substitute the value of the volume of water displaced into the buoyant force formula to calculate the buoyant force acting on the plastic object.

Fb = ρwater * (0.5g / ρwater) * g

Simplifying the equation, we find that the density of water cancels out, leaving us with:

Fb = 0.5g

Therefore, the buoyant force acting on the plastic object is equal to 0.5g, where g is the acceleration due to gravity (approximately 9.8 m/s²).

Conclusion
When a plastic object displaces 0.5g of water, the buoyant force acting on the object is equal to 0.5g. This buoyant force is a result of Archimedes' principle and is proportional to the weight of the fluid displaced by the object.
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A plastic object of mass 0.5 kg is immersed in water.The buoyant force acting on the object if it displaces 0.5g of water?
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A plastic object of mass 0.5 kg is immersed in water.The buoyant force acting on the object if it displaces 0.5g of water? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A plastic object of mass 0.5 kg is immersed in water.The buoyant force acting on the object if it displaces 0.5g of water? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A plastic object of mass 0.5 kg is immersed in water.The buoyant force acting on the object if it displaces 0.5g of water?.
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