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A block of mass m is placed on an another rough block of mass M and both are moving horizontally with same acceleration a due to a force which is applied on the lower block, then work done by lower block on the upper block in moving a distance s will be
a) mas
b) ( m + M ) as
C) M2/m as
d) None of these
Correct answer is option 'A'. Can you explain this answer?
a) mas
b) ( m + M ) as
C) M2/m as
d) None of these
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A block of mass m is placed on an another rough block of mass M and bo...
Force on the upper block = ma Work done = F.S = mas
This question is part of UPSC exam. View all Class 11 courses
Most Upvoted Answer
A block of mass m is placed on an another rough block of mass M and bo...
Work done by a force is given by the product of the force and the displacement in the direction of the force. In this case, the lower block is exerting a force on the upper block, causing it to move a distance s. So, we need to calculate the work done by the lower block on the upper block.
Let's consider the forces acting on the upper block. There are two forces acting on it: the force of gravity (mg) acting downwards and the force exerted by the lower block (F) acting to the right. The force of gravity does not do any work on the upper block because the displacement is perpendicular to the force.
The net force acting on the upper block is the force exerted by the lower block (F) minus the force of friction (f) between the two blocks. So, the net force is given by:
Net force = F - f
The force of friction can be calculated using the equation:
f = μN
where μ is the coefficient of friction between the two blocks and N is the normal force. The normal force is equal to the weight of the upper block, which is Mg.
So, the force of friction can be written as:
f = μMg
Since the blocks are moving with the same acceleration, the force of friction is equal to the mass of the upper block (m) times the acceleration (a). Therefore, we have:
μMg = ma
Simplifying the equation, we get:
μ = a/g
Now, we can calculate the net force:
Net force = F - f
= F - μMg
= F - (a/g)Mg
= F - (a/g)Mg
The work done by the lower block on the upper block is given by the product of the net force and the displacement (s) in the direction of the force. So, we have:
Work = (F - (a/g)Mg)s
Since the force exerted by the lower block is equal to mas, we can substitute it into the equation:
Work = (mas - (a/g)Mg)s
= mas^2 - (a/g)Mgs
Simplifying the equation, we get:
Work = mas^2 - (a/g)Mgs
= mas^2 - as^2
= (m - a)s^2
Therefore, the work done by the lower block on the upper block is (m - a)s^2. This means that the correct answer is option A, mas.
Let's consider the forces acting on the upper block. There are two forces acting on it: the force of gravity (mg) acting downwards and the force exerted by the lower block (F) acting to the right. The force of gravity does not do any work on the upper block because the displacement is perpendicular to the force.
The net force acting on the upper block is the force exerted by the lower block (F) minus the force of friction (f) between the two blocks. So, the net force is given by:
Net force = F - f
The force of friction can be calculated using the equation:
f = μN
where μ is the coefficient of friction between the two blocks and N is the normal force. The normal force is equal to the weight of the upper block, which is Mg.
So, the force of friction can be written as:
f = μMg
Since the blocks are moving with the same acceleration, the force of friction is equal to the mass of the upper block (m) times the acceleration (a). Therefore, we have:
μMg = ma
Simplifying the equation, we get:
μ = a/g
Now, we can calculate the net force:
Net force = F - f
= F - μMg
= F - (a/g)Mg
= F - (a/g)Mg
The work done by the lower block on the upper block is given by the product of the net force and the displacement (s) in the direction of the force. So, we have:
Work = (F - (a/g)Mg)s
Since the force exerted by the lower block is equal to mas, we can substitute it into the equation:
Work = (mas - (a/g)Mg)s
= mas^2 - (a/g)Mgs
Simplifying the equation, we get:
Work = mas^2 - (a/g)Mgs
= mas^2 - as^2
= (m - a)s^2
Therefore, the work done by the lower block on the upper block is (m - a)s^2. This means that the correct answer is option A, mas.
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A block of mass m is placed on an another rough block of mass M and both are moving horizontally with same acceleration a due to a force which is applied on the lower block, then work done by lower block on the upper block in moving a distance s will bea)masb)( m + M ) asC) M2/m asd)None of theseCorrect answer is option 'A'. Can you explain this answer?
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A block of mass m is placed on an another rough block of mass M and both are moving horizontally with same acceleration a due to a force which is applied on the lower block, then work done by lower block on the upper block in moving a distance s will bea)masb)( m + M ) asC) M2/m asd)None of theseCorrect answer is option 'A'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A block of mass m is placed on an another rough block of mass M and both are moving horizontally with same acceleration a due to a force which is applied on the lower block, then work done by lower block on the upper block in moving a distance s will bea)masb)( m + M ) asC) M2/m asd)None of theseCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A block of mass m is placed on an another rough block of mass M and both are moving horizontally with same acceleration a due to a force which is applied on the lower block, then work done by lower block on the upper block in moving a distance s will bea)masb)( m + M ) asC) M2/m asd)None of theseCorrect answer is option 'A'. Can you explain this answer?.
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