Class 12 Exam > Class 12 Questions > In the equation Kt = log C0 – log Ct, t...
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In the equation Kt = log C0 – log Ct, the curve between t and log Ct is -
[AIEEE-2002]
- a)a straight line
- b)a parabola
- c)a hyperbola
- d)none
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
In the equation Kt = log C0 – log Ct, the curve between t and lo...
The correct answer is option A
Compare straight line equation
(y = mx + c) with Kt = -log (Ct) + log(C0)
where,
K being constant,
"t" is equivalent to "y" in straight line equation
(-1) is slope for equation which is "m" in straight line equation
log (Ct) is x-component
& log (C0) is y-intercept.
Compare straight line equation
(y = mx + c) with Kt = -log (Ct) + log(C0)
where,
K being constant,
"t" is equivalent to "y" in straight line equation
(-1) is slope for equation which is "m" in straight line equation
log (Ct) is x-component
& log (C0) is y-intercept.
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Community Answer
In the equation Kt = log C0 – log Ct, the curve between t and lo...
Compaire straight line equation
(y = mx + c) with Kt = -log(Ct) + log(C0)
, where , K being constant ,
"t" is equivalent to "y" in straight line equation
(-1) is slope for equation which is "m" in straight line equation
log(Ct) is x-component
& log(C0) is y-intercept
(y = mx + c) with Kt = -log(Ct) + log(C0)
, where , K being constant ,
"t" is equivalent to "y" in straight line equation
(-1) is slope for equation which is "m" in straight line equation
log(Ct) is x-component
& log(C0) is y-intercept
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In the equation Kt = log C0 – log Ct, the curve between t and log Ct is -[AIEEE-2002]a)a straight lineb)a parabolac)a hyperbolad)noneCorrect answer is option 'A'. Can you explain this answer?
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