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A stone of mass of 16 kg is attached to a string 144 m long and is whirled in a horizontal smooth surface. The maximum tension the string can withstand is 16 newton. The maximum speed of revolution of the stone without breaking it, will be :
- a)20 ms-1
- b)16 ms-1
- c)14 ms-1
- d)12 ms-1
Correct answer is option 'A,C,D'. Can you explain this answer?
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Verified Answer
A stone of mass of 16 kg is attached to a string 144 m long and is whi...
T= (mv2max)/r
16 = (16 v2max)/144
v2max = 12 m/s
16 = (16 v2max)/144
v2max = 12 m/s
Most Upvoted Answer
A stone of mass of 16 kg is attached to a string 144 m long and is whi...
Analysis:
The stone is undergoing circular motion in a horizontal plane with a maximum tension of 16 N.
Centripetal Force:
The tension in the string provides the centripetal force required to keep the stone in circular motion.
Centripetal Force Formula:
\( F_{\text{centripetal}} = \frac{mv^2}{r} \)
Maximum Tension:
The maximum tension the string can withstand is 16 N.
Calculations:
Given mass, m = 16 kg
Length of the string, r = 144 m
Maximum tension, T = 16 N
Maximum Speed:
- Using the formula for centripetal force, we can find the maximum speed of revolution without breaking the string.
- \( T = \frac{m v^2}{r} \)
- \( v^2 = \frac{T \cdot r}{m} \)
- \( v^2 = \frac{16 \cdot 144}{16} \)
- \( v^2 = 144 \)
- \( v = \sqrt{144} \)
- \( v = 12 \, \text{ms}^{-1} \)
Therefore, the maximum speed of revolution of the stone without breaking the string is 12 ms-1.
The stone is undergoing circular motion in a horizontal plane with a maximum tension of 16 N.
Centripetal Force:
The tension in the string provides the centripetal force required to keep the stone in circular motion.
Centripetal Force Formula:
\( F_{\text{centripetal}} = \frac{mv^2}{r} \)
Maximum Tension:
The maximum tension the string can withstand is 16 N.
Calculations:
Given mass, m = 16 kg
Length of the string, r = 144 m
Maximum tension, T = 16 N
Maximum Speed:
- Using the formula for centripetal force, we can find the maximum speed of revolution without breaking the string.
- \( T = \frac{m v^2}{r} \)
- \( v^2 = \frac{T \cdot r}{m} \)
- \( v^2 = \frac{16 \cdot 144}{16} \)
- \( v^2 = 144 \)
- \( v = \sqrt{144} \)
- \( v = 12 \, \text{ms}^{-1} \)
Therefore, the maximum speed of revolution of the stone without breaking the string is 12 ms-1.
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Community Answer
A stone of mass of 16 kg is attached to a string 144 m long and is whi...
T= mv2/ r.....v= 12 m/ s...But how cum 20, 14 are also the answers???
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A stone of mass of 16 kg is attached to a string 144 m long and is whirled in a horizontal smooth surface. The maximum tension the string can withstand is 16 newton. The maximum speed of revolution of the stone without breaking it, will be :a)20 ms-1b)16 ms-1c)14 ms-1d)12 ms-1Correct answer is option 'A,C,D'. Can you explain this answer?
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A stone of mass of 16 kg is attached to a string 144 m long and is whirled in a horizontal smooth surface. The maximum tension the string can withstand is 16 newton. The maximum speed of revolution of the stone without breaking it, will be :a)20 ms-1b)16 ms-1c)14 ms-1d)12 ms-1Correct answer is option 'A,C,D'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A stone of mass of 16 kg is attached to a string 144 m long and is whirled in a horizontal smooth surface. The maximum tension the string can withstand is 16 newton. The maximum speed of revolution of the stone without breaking it, will be :a)20 ms-1b)16 ms-1c)14 ms-1d)12 ms-1Correct answer is option 'A,C,D'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A stone of mass of 16 kg is attached to a string 144 m long and is whirled in a horizontal smooth surface. The maximum tension the string can withstand is 16 newton. The maximum speed of revolution of the stone without breaking it, will be :a)20 ms-1b)16 ms-1c)14 ms-1d)12 ms-1Correct answer is option 'A,C,D'. Can you explain this answer?.
A stone of mass of 16 kg is attached to a string 144 m long and is whirled in a horizontal smooth surface. The maximum tension the string can withstand is 16 newton. The maximum speed of revolution of the stone without breaking it, will be :a)20 ms-1b)16 ms-1c)14 ms-1d)12 ms-1Correct answer is option 'A,C,D'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A stone of mass of 16 kg is attached to a string 144 m long and is whirled in a horizontal smooth surface. The maximum tension the string can withstand is 16 newton. The maximum speed of revolution of the stone without breaking it, will be :a)20 ms-1b)16 ms-1c)14 ms-1d)12 ms-1Correct answer is option 'A,C,D'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A stone of mass of 16 kg is attached to a string 144 m long and is whirled in a horizontal smooth surface. The maximum tension the string can withstand is 16 newton. The maximum speed of revolution of the stone without breaking it, will be :a)20 ms-1b)16 ms-1c)14 ms-1d)12 ms-1Correct answer is option 'A,C,D'. Can you explain this answer?.
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