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The resistance of four arms of a Wheatstone bridge are 10,10,10,30.what amount of resistance should be added with 30ohm resistance to get the null condition.?
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The resistance of four arms of a Wheatstone bridge are 10,10,10,30.wha...
15 ohm should be joined parallel to 30 ohms.....consider P=10,Q=10,R=10,S=30..for balanced condition in wheat stone bridge..P/Q=R/S..let S be x..10/10=10/x.x=10. given S=30 ohm.so ...30 × X/30+X=10.30X=300+10X.X=15...now if we connect 15 ohms parallel to 30 ohms..then the wheat stone bridge is balanced...
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The resistance of four arms of a Wheatstone bridge are 10,10,10,30.wha...
15ohm inparallel
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The resistance of four arms of a Wheatstone bridge are 10,10,10,30.what amount of resistance should be added with 30ohm resistance to get the null condition.?
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