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Consider the following differential equation:
Which of the following is the solution of the above equation (c is an arbitrary constant)?
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Consider the following differential equation:Which of the following is...
Divide both the sides by (x^2) dx
All the terms are now in the form of (y/x) and dy/dx
Now put (y/x)=v
so that dy/dx = v+x(dv/dx). | by product rule
simplifying it you'll get something like this
(dv/dx) = (2v*cosv)/(vsinv - cosv)

[ (vsinv - cosv)/2vcosv] dv = dx/x

simplifying some more
[ ( tanv/2) - 1/2v ] dv = dx/x

Now integrate simply and you'll get
(1/2) [ log|secv| - logv ] = log x + log c

simplify it (1/2) [ log(secv/v) ] = log(cx)
log √(secv/v) = log (cx)

√(secv/v) = cx
secv/v = (cx)square
since c^2 is also a constant you can take it as other constant say c again

[ 1/vcosv ] = cx^2

[ x/ycos(y/x) ] = cx^2


now 1/c will again be a constant and I'm taking it as 'c' again

xycos(y/x) = c
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Consider the following differential equation:Which of the following is the solution of the above equation (c is an arbitrary constant)?a)b)c)d)Correct answer is option 'C'. Can you explain this answer?
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