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The maximum permissible deflection for a gantry girder, spanning over 6 m, on which an EOT (electric overhead travelling) crane of capacity 200 kN is operating, is
- a)8 mm
- b)10 mm
- c)12 mm
- d)18 mm
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
The maximum permissible deflection for a gantry girder, spanning over ...
Maximum vertical deflection of Gantry girder for EOT of capacity less than 500KN is ( L/750), where L in mm
For EOT having capacity more then 500KN deflection is (L/1000) and for manually operated crane Deflection is (L/500)
For EOT having capacity more then 500KN deflection is (L/1000) and for manually operated crane Deflection is (L/500)
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The maximum permissible deflection for a gantry girder, spanning over ...
Maximum Permissible Deflection for Gantry Girder
Gantry girder is a structural member that supports the electric overhead traveling (EOT) crane. The maximum permissible deflection for a gantry girder is the maximum amount of deformation or bending that the girder can withstand without causing any damage.
Given Parameters
- Span of the gantry girder = 6 m
- Capacity of the EOT crane = 200 kN
Calculation
The maximum permissible deflection for a gantry girder can be calculated using the following formula:
δmax = (wL^3) / (48EI)
where,
- δmax = maximum permissible deflection
- w = uniformly distributed load on the girder
- L = span of the girder
- E = modulus of elasticity of the girder material
- I = moment of inertia of the girder section
Assuming a uniformly distributed load, the weight of the EOT crane is distributed over the span of the girder. Therefore, the load on the girder can be calculated as:
w = (Capacity of the EOT crane) / (Span of the girder)
w = 200 kN / 6 m
w = 33.33 kN/m
The modulus of elasticity and moment of inertia of the girder section depend on the material and cross-sectional shape of the girder. For simplicity, assume a rectangular cross-section made of mild steel.
The modulus of elasticity of mild steel is 2 x 10^5 MPa.
The moment of inertia of a rectangular section is (bh^3) / 12, where b is the width of the section and h is the depth of the section. Assume a width of 200 mm and a depth of 400 mm.
I = (200 x 400^3) / 12
I = 85.33 x 10^6 mm^4
Substituting the values in the formula, we get:
δmax = (33.33 x 6^3) / (48 x 2 x 10^5 x 85.33 x 10^6)
δmax = 0.008 m = 8 mm
Therefore, the maximum permissible deflection for the gantry girder is 8 mm.
Gantry girder is a structural member that supports the electric overhead traveling (EOT) crane. The maximum permissible deflection for a gantry girder is the maximum amount of deformation or bending that the girder can withstand without causing any damage.
Given Parameters
- Span of the gantry girder = 6 m
- Capacity of the EOT crane = 200 kN
Calculation
The maximum permissible deflection for a gantry girder can be calculated using the following formula:
δmax = (wL^3) / (48EI)
where,
- δmax = maximum permissible deflection
- w = uniformly distributed load on the girder
- L = span of the girder
- E = modulus of elasticity of the girder material
- I = moment of inertia of the girder section
Assuming a uniformly distributed load, the weight of the EOT crane is distributed over the span of the girder. Therefore, the load on the girder can be calculated as:
w = (Capacity of the EOT crane) / (Span of the girder)
w = 200 kN / 6 m
w = 33.33 kN/m
The modulus of elasticity and moment of inertia of the girder section depend on the material and cross-sectional shape of the girder. For simplicity, assume a rectangular cross-section made of mild steel.
The modulus of elasticity of mild steel is 2 x 10^5 MPa.
The moment of inertia of a rectangular section is (bh^3) / 12, where b is the width of the section and h is the depth of the section. Assume a width of 200 mm and a depth of 400 mm.
I = (200 x 400^3) / 12
I = 85.33 x 10^6 mm^4
Substituting the values in the formula, we get:
δmax = (33.33 x 6^3) / (48 x 2 x 10^5 x 85.33 x 10^6)
δmax = 0.008 m = 8 mm
Therefore, the maximum permissible deflection for the gantry girder is 8 mm.
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Community Answer
The maximum permissible deflection for a gantry girder, spanning over ...
Maximum vertical deflection of Gantry girder for EOT of capacity less than 500KN is ( L/750), where L in mm
For EOT having capacity more then 500KN deflection is
(L/1000)
and for manually operated crane Deflection is (L/500)
For EOT having capacity more then 500KN deflection is
(L/1000)
and for manually operated crane Deflection is (L/500)
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The maximum permissible deflection for a gantry girder, spanning over 6 m, on which an EOT (electric overhead travelling) crane of capacity 200 kN is operating, isa)8 mmb)10 mmc)12 mmd)18 mmCorrect answer is option 'A'. Can you explain this answer?
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