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If z3-z1/z2-z1 is a real number then show that that points represented by the complex numbers z1,z2,z3 are collinear?
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If z3-z1/z2-z1 is a real number then show that that points represented...
Ans.

Let z1 = x1 + iy1
z2 = x2 + iy2
z3 = x2 + iy3

So, (z3 - z1)/(z2 - z1)
= (x3 + iy3 - x1 - iy1)/(x2 + iy2 - x1 - iy1)
For this to be Real
(from the numerator)
iy3 - iy1 = 0
Taking out the i's
y3 - y1 = 0___(1)

(from the denominator)
iy2 - iy1 = 0
Taking out the i's
y2 - y1 = 0___(2)

(1) - (2)
y3 - y2 = 0___(3)


Okay so on the Argand Plane, Let
z1 = A
z2 = B
z3 = C

If they're collinear, mAB = mBC = mAC
m is the gradient (rise over run)
mAB = (y2 - y1)/(x2 - x1)
= 0/(x2 - x1) (from (2))
= 0
mBC = (y3 - y2)/(x3 - x2)
= 0/(x3 - x2) (from (3))
= 0
mAC = (y3 - y1)/(x3 - x1)
= 0/(x3 - x1) (from (1))
= 0
And since the gradient is all the same, they're all collinear (and in fact, on a line parallel to the x axis)

This question is part of UPSC exam. View all Class 12 courses
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If z3-z1/z2-z1 is a real number then show that that points represented...
Proof:

Let's assume that the complex numbers z1, z2, and z3 are represented as follows:

z1 = x1 + y1i,
z2 = x2 + y2i,
z3 = x3 + y3i,

where x1, y1, x2, y2, x3, and y3 are real numbers.

We are given that the expression (z3 - z1) / (z2 - z1) is a real number.

Step 1: Simplify the expression (z3 - z1) / (z2 - z1)

(z3 - z1) / (z2 - z1) = [(x3 + y3i) - (x1 + y1i)] / [(x2 + y2i) - (x1 + y1i)]
= [(x3 - x1) + (y3 - y1)i] / [(x2 - x1) + (y2 - y1)i]

To make the expression a real number, the imaginary part must be zero. Therefore, we have:

y3 - y1 = 0,
y3 = y1.

Step 2: Rewrite the complex numbers z1, z2, and z3

Using the result from Step 1, we can rewrite z3 as:

z3 = x3 + y1i.

Now, let's rewrite the expression (z3 - z1) / (z2 - z1) using the new representation of z3:

(z3 - z1) / (z2 - z1) = [(x3 + y1i) - (x1 + y1i)] / [(x2 + y2i) - (x1 + y1i)]
= [(x3 - x1) + (y1 - y1)i] / [(x2 - x1) + (y2 - y1)i]
= (x3 - x1) / (x2 - x1).

Step 3: Interpretation

The expression (x3 - x1) / (x2 - x1) is a real number, which means the imaginary part of this expression is zero. Therefore, we have:

0 = Im[(x3 - x1) / (x2 - x1)]
= (x3 - x1)(x2 - x1)^(-1) - (x3 - x1)(x2 - x1)^(-1)
= 0.

This implies that the imaginary part of (z3 - z1) / (z2 - z1) is zero, which means the expression represents a real number.

Conclusion:

Since the expression (z3 - z1) / (z2 - z1) is a real number, we have shown that the points represented by the complex numbers z1, z2, and z3 are collinear.
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If z3-z1/z2-z1 is a real number then show that that points represented by the complex numbers z1,z2,z3 are collinear?
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